4
$\begingroup$

I've found on Wikipedia that energy $E$ and angular momentum $L$ of a particle are conserved quantities in Schwarzschild metric. It's written:

$$L=mr^2 \frac {d\phi} {d\tau},$$

$$E=mc^2\left(1-\frac{r_s}{r}\right)\frac{dt}{d\tau}.$$

And, from the metric, it finds these results:

$$\left(\frac{d\phi}{d\tau}\right)^2=\frac{L^2}{m^2r^4}$$

$$\left(\frac{dr}{d\tau}\right)^2=\frac{E^2}{m^2c^2}-\left(1-\frac{r_s}{r}\right)\left(c^2+\frac{L^2}{m^2r^2}\right).$$

$$\left(\frac{dt}{d\tau}\right)^2=\frac{E}{\left(1-\frac{r_s}{r}\right)mc^2}$$

That I need is to get the results including also the $\theta$ coordinate. So I tried this:

$$p_\phi=mr^2 \frac {d\phi} {d\tau}\qquad\qquad p_\theta=mr^2 \frac {d\theta} {d\tau}$$

$$L^2=p_\theta^2 + \sin^2\theta\ p_\phi^2.$$

$E$ is the same?

$$\left(\frac{d\phi}{d\tau}\right)^2=\frac{p_\phi^2}{m^2r^4}\qquad\qquad \left(\frac{d\theta}{d\tau}\right)^2=\frac{p_\theta^2}{m^2r^4}.$$

$\frac{dr}{d\tau}$ is the same?

$\frac{dt}{d\tau}$ is the same?

But I'm not sure. However, is it possible to get a similar result adding the $\theta$ coordinate?

PS: I am a beginner about GR, so I don't know many things about it.

$\endgroup$
4
  • $\begingroup$ In the Schwarzschild analysis $\theta$ is normally take to be some constant, say $\pi/2$, and then motion in the equatorial plane is analyzed as a function of the longitudinal angle, $\varphi$. This is sufficient for analyzing light-bending and periastron precession. If $\theta$ is not constant, then the orbital plane itself precesses, with a tilt from the z-axis given by $\theta$. Are you sure this is what you want to analyze? If so, why? $\endgroup$
    – Bruce Dean
    Commented Jan 5, 2014 at 4:00
  • $\begingroup$ I'm developing a 3D application which simulates the motion around a black hole, so I need to have a non-constant $\theta$ coordinate, I think... $\endgroup$
    – Ale
    Commented Jan 5, 2014 at 14:44
  • $\begingroup$ Hi user2108312. Welcome to Phys.SE. If you haven't already done so, please take a minute to read the definition of when to use the homework tag, and the Phys.SE policy for homework-like problems. $\endgroup$
    – Qmechanic
    Commented Jan 5, 2014 at 15:01
  • $\begingroup$ I've read. So is this a homework question? $\endgroup$
    – Ale
    Commented Jan 5, 2014 at 15:22

2 Answers 2

1
$\begingroup$

Rotate the coordinates so that you reduce your problem to the 'standard' treatment with $\theta$ constant, solve it, and then rotate again the coordinates to get the solution in the original system.

The orbit is in the plane identified by the position ($\vec r$) and velocity ($\vec v$) vectors. This plane should be rotated so that it becomes the $xy$ plane. The vector normal to the orbit plane is $\hat n = (\vec r \times \vec v) / (rv)$, that should be rotated to become the $z$ axis - so the rotation axis is $\hat n \times \hat z$ and the rotation angle is $\arccos(\hat n \cdot \hat z)$

$\endgroup$
3
  • $\begingroup$ The problem becomes how much should I rotate... $\endgroup$
    – Ale
    Commented Jan 5, 2014 at 17:47
  • $\begingroup$ ...see expanded answer - I did not do the complete work, but there should be enough to get you going $\endgroup$
    – MiMo
    Commented Jan 5, 2014 at 18:03
  • $\begingroup$ Many thanks! I will try that, but now I can't. $\endgroup$
    – Ale
    Commented Jan 5, 2014 at 18:23
0
$\begingroup$

What you really want are two sections of wikipedia: https://en.wikipedia.org/wiki/Schwarzschild_geodesics#Mathematical_derivations_of_the_orbital_equation https://en.wikipedia.org/wiki/Schwarzschild_geodesics#Orbits_of_test_particles

It might be tough going for a while but understanding those will keep you from egregious errors. Such that I (and others) have made.

I think some expansion of the question is appropriate.
A more correct question would be:
1)Given a mathematical description of a physical situation can we find invariants for certain types of orbits/paths/histories.
i.e. In the case: What are the invariants of geodesic paths/orbits in the Schwarzschild metric? BTW a fixed point with "time" (time is not a fixed coordinate for different coordinate systems) as the only variable is not a geodesic.
Then:
2)Can we identify these invariants with energy and momentum conservation?

The first part is answered by a Theorem/construction/proof; inside of mathematical physics, it is not a given! Although in our limited physics experience the conservation of energy and angular momentum have proven true and useful; in mathematical physics they must be reproved for separate situations.
As far as I know the questions are unresolved for general situations in GR.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.