The nerve impulse transmission is specifically a biophysical process. Under a resting stage, the membrane is already polarised (presence of charge on either side leading to a potential difference across it, due to its finite capacitance). Changes in this polarisations mediated by several agents, cause some part of this membrane to be depolarised (inversion of the charges in that localised area). This changes the potential difference across that region and starts ion flow from the depolarised region of the membrane to the adjacent polarised region, inducing the same depolarisation there. Myelinating a neuron is similar to lowering the capacitance of the neuron. Myelinating the neuron causes subsequent action potentials to be spatially separated, and the conduction of voltage between them occurs primarily through ion flow along the neuron. Here are some nerve conduction basics.
Now my actual question. Modelling a neuron as a simple one dimensional membrane/cable, how can a lowered capacitance lead to a faster conduction of the voltage perturbation i.e a change in voltage (depolarisation), which is initially limited to a small localised region? This conduction of the voltage change can occur through the ion flow along the inner side of the membrane and also due to long distance changes in potential due to the altered distribution of charges along the membrane. A very good physical modelling of the neuron is given here and here, but because of the quite complicated mathematical nature of the modified telegrapher's equation which appears as the final answer, I am unable to understand how lowered capacitance increases the speed of voltage conduction?
Tell me if this question is off-topic or too biological to be answered here.