Assume that an object has negligible height, i.e., height is approximately $0m$.
If we immerse this object in water, will it float or sink? In order to find this out, we need to calculate the net force acting on the object. I am considering $3$ main forces acting on the object. The first of these forces is the force exerted by the molecules of the liquid at the top of the object in the downward direction, which we will call $F_d$. The second force is the weight force acting on the object in the downward direction, which is $F_W$. Thirdly, we have the force exerted by the molecules of the liquid at the bottom of the object in the upward direction, which we will call $F_u$.
To find the net force acting on the object: $$F_{net} = (F_d + F_W) - F_u$$
The pressure exerted by the liquid at the top of the object is $P_t$ and that exerted at the bottom of the object is $P_b$. As the height is approximately $0$, we will consider the $P_t$ and $P_b$ to be equal. Also, again as the height is negligible, the area at the top and the bottom of the object, i.e., $A_t$ and $A_b$ will also be equal.
We know that $P=\frac{F}{A}$. Thus to find force, $F = PA$.
$F_d = P_tA_t$
$F_u = P_dA_d$
$P_tA_t = P_dA_d$ as pressure and area at the top and bottom are equal.
$$F_{net} = (P_tA_t + F_W) - P_dA_d$$ $$F_{net} = (PA + F_W) - PA$$ $$F_{net} = F_W$$
According to this, the net force acting on the object at any height would always be $F_W$ and, of course, always in the downward direction, thus signifying that it would always sink, regardless of density of the substance, height in the liquid, volume of liquid displaced, etc.
Is this conclusion true or is my understanding of the concept or the equations flawed at any point?