In a Conformal Field Theory in arbitrary dimensions, four-point functions are constrained to take the form
$$\langle O_1(x_1)O_2(x_2)O_3(x_3)O_4(x_4)\rangle = K(x_i)F(z,\bar z)$$
where $K(x_i)$ is a conformally-covariant prefactor and $(z,\bar z)$ are the cross ratios defined by $$u = \dfrac{x_{12}^2x_{34}^2}{x_{13}^2x_{24}^2},\quad v=\dfrac{x_{14}^2x_{23}^2}{x_{13}^2x_{24}^2},\quad u=z\bar z,\quad v=(1-z)(1-\bar z).$$
The function $F(z,\bar z)$ is constrained by crossing symmetry in any number of dimensions, but apart from that it is arbitrary. Now in a two-dimensional CFT apart from the global conformal symmetry we have the local Virasoro symmetry as well. So it would seem to me that there had to be some signature of this Virasoro symmetry in the corresponding $F(z,\bar z)$.
In other words: in any number of dimensions a four-point function is given by prescribing some function $F(z,\bar z)$. In that case, if I were given some $F(z,\bar z)$ how can I check whether this particular choice is compatible with Virasoro symmetry - and so a possible two-dimensional four-point function - or not, and hence not a two-dimensional four-point function? What is the signature of Virasoro symmetry left in $F(z,\bar z)$?