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When calculating the amount of power available from a water outlet (using a system that converts the kinetic energy of the water flow to power with for example a Pelton wheel), the energy per unit time is different depending on the nozzle size and hence flowrate of the water leaving the outlet.

In a hypothetical perfect system where total volume of water out is the same regardless of nozzle diameter (but hence the speed varies inversely with nozzle area), how is it that more energy is available ($\frac{1}{2}mv^2$) at higher speeds, when surely the potential energy in the system is a very specific fixed value.

Of course in reality the mass flowrate will reduce with nozzle area reduction - but hypothetically I don't understand why there is an apparent difference in energy potential between the configurations.

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  • $\begingroup$ You seem to be comparing power to potential energy, why do you think these have to be the same? Also, water as a large continuous body wouldn't have just one potential energy. $\endgroup$
    – Triatticus
    Commented Jun 8, 2023 at 11:53
  • $\begingroup$ No I was noting that the energy available per second (power) was different in different scenarios from the same energy source. What I was missing was "pressure energy" as explained in the currently accepted answer. $\endgroup$
    – Claud
    Commented Jun 13, 2023 at 8:04

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how is it that more energy is available ($\frac{1}{2}mv^2$) at higher speeds, when surely the potential energy in the system is a very specific fixed value.

You are only accounting for the potential energy and kinetic energy of the flow and neglecting pressure energy (see Bernoulli equation). There is a lowering of pressure in the constriction. In the high velocity flow through the constriction, kinetic energy must increase at the expense of pressure energy.

For more details, see http://hyperphysics.phy-astr.gsu.edu/hbase/pber.html

Hope this helps.

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