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Let's say, I have some quantities in unit $ \rm kg^{-1/2}$, I now want to express the quantity in $\rm g^{-1/2}$. Do I simply multiply the quantity by $\rm k^{-1/2}$ which is approximately $0.0316$ ?

The way I am going about this is that since $\rm kg^{-1/2}$ can be separated into $\rm k^{-1/2}×g^{-1/2}$, and so the quantity has to 'absorb' $\rm k^{-1/2}$.

I'm asking this question because I tend to run into a lot of units with strange exponents when doing data analysis and need a sanity check.

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  • $\begingroup$ you are totally correct. $\endgroup$
    – sleepy
    Commented Mar 27, 2021 at 20:07

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You probably learned the prefixes

  • Mega = $10^6$
  • Kilo = $10^3$
  • Milli = $10^{-3}$

So, all you have to do is using them in the relationship you are interested in. E.g. $$\pi \frac{(kg)^{1/3} \; \cdot MJ}{(mV)^4} = \pi \frac{(10^3g)^{1/3} \; \cdot (10^6J)}{(10^{-3}V)^4} = \pi \frac{10g^{1/3} \; \cdot 10^6J}{10^{-3/4}V^4} = \ldots $$

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