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I have read a lot of questions on this site about neutrino absorption, and all of them mention that usually when a neutron transforms into a proton or vica versa, that is really an up quark transforms into a down quark or vica versa, a neutrino is absorbed (or emitted).

Now none of these say whether the word absorption is used as in fact the neutrino being absorbed by a specific particle, that is the neutron or the proton as a whole system, or just a quark (though in confinement), as a separate elementary particle.

Is it correct to view this as analogous to photon absorption, where a free electron cannot absorb a photon (except when accelerating in an external magnetic field), but it is really the atom/electron system that absorbs the photon.

Is it the same with a neutrino, where the whole neutron or proton (quark, antiquark, gluon sea) can only absorb the neutrino, and not the quark itself?

I have read this:

https://arxiv.org/pdf/0804.3899.pdf

And it is talking about quark-neutrino scattering (elastic).

https://en.wikipedia.org/wiki/Weak_interaction

This wiki site does not mention neutrino absorption, just emission in certain cases. Usually the process is described by a intermediary (virtual) W or Z bozon transforming into a neutrino and another lepton.

Question:

1.In neutrino absorption, what is it really that absorbs the neutrino?

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    $\begingroup$ This en.wikipedia.org/wiki/Neutrino#Detection mentions a particle interaction that removes a neutrino. That's all that absorption or capture is meaning. There does not have to be a "thing" that absorbs the neutrino. The neutrino mode in the field fades away and is replaced by other modes. $\endgroup$ Commented Apr 1, 2020 at 22:23
  • $\begingroup$ @PonderStibbons neutrinos have energy (rest mass) and that is converted into the energy of another field, another QM entity, like the neutron or proton or quark. Maybe like a photon's energy is converted into the electrons field's energy (atom/electron system). Energy and momentum has to be conserved and the neutrino's energy has to be converted into another field's energy, I just do not know which one. $\endgroup$ Commented Apr 1, 2020 at 22:39
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    $\begingroup$ I suggest that you look at the Standard Model vertices to understand everything that can possibly happen to a neutrino. They never get directly absorbed by protons, or neutrons, or quarks. $\endgroup$
    – G. Smith
    Commented Apr 1, 2020 at 23:45

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It could be said that in proton + neutrino = neutron + electron, an up quark in the proton is converted to a down quark in the neutron, using up 2.2 Mev. But also leaving us short on 1 electron charge. Another 0.5 Mev gives us the electron which also collects the charge. In this sense, the energy of the neutrino is distributed to both of the products of the particle interaction. But, the proton could also have had kinetic energy that it brings to the reaction. It is not possible, on the current theory, to track explicitly the energy that was originally in the proton or the neutrino and see where it went after the reaction, and that question might have no meaning. Energy is not particles, it is more just a number that is conserved. Compute it before and compute it after, it is the same.

The same question could be asked of a collection of pulleys and weights. Two weights move down and two weights move up. But, the theory does not say where the energy of the original two weights went, only that the total over all the weights is unchanged.

Addendum:

If one insists on having an energy operator and applying it to the fields, then one has an energy density, and coupling this with a momentum operator, an energy flux. In principle one could then follow the stream lines of the energy flow and determine in a sense, by putting a surface around a region and calling it the neutrino, where the energy had gone. In this case, I would expect that it depends on the details of the geometry of the specific interaction.

Compare with the idea of lowering one weight first and raising one at the same time, and then lowering the second weight and raising the second in the previous example. Arguably, in this case the 1st lowered weight energy went to the 1st raised weight. But this conclusion depends on the details of the particular instance of the reaction.

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