0
$\begingroup$

Neptunium-236 has a half-life of about 154,000 years, which is quite long for an isotope with odd numbers of both protons an neutrons, correct?

Other 'odd-odd' nuclides with longer-than-expected half-lifes can only decay by going through major changes in spin, so are considered 'high-spin stabilized'. But I cannot find a place where it specifically says this about Np-236......

$\endgroup$

1 Answer 1

3
$\begingroup$

The quantity $Z^2/A$ equals 36.6 for this isotope, which makes it not have any significant probability of decay by spontaneous fission. See https://en.wikipedia.org/wiki/Spontaneous_fission .

In alpha decay, its daughter will also be odd-odd, so the alpha decay half-life doesn't get shorter just because it's odd-odd. Its $Z$ isn't very high, so it's not surprising that alpha decay is weak.

That leaves beta decay and electron capture. Its main mode of decay is electron capture.

Other 'odd-odd' nuclides with longer-than-expected half-lifes can only decay by going through major changes in spin, so are considered 'high-spin stabilized'. But I cannot find a place where it specifically says this about Np-236......

Did you try looking at ENSDF?

Jπ: High log ft′s in β−, ε decays suggest large K value. Nilsson level syst (1972El21) suggests Jπ=6−. β− and ε decays to 6+ levels in 236Pu and 236U are consistent with J=6.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.