I think that your $V$ is just $A/C$. So what you need to do is to express $f(x)$ in terms of the parameters you are actually interested in. e.g.
$$ f(x) = A \left( \sin(\omega x + B) + \frac{1}{V} \right), $$
or
$$ f(x) = C\left( V \sin(\omega x + B) + 1 \right), $$
and fit one of these functions using your least squares approach.
Neither is going to be perfect, or at least the uncertainties are not going to be perfect, because there will be some correlation between the parameter uncertainties.
EDIT: Your comments reveal that you don't know how to find any of the uncertainties. This is a standard text-book bit of statistics. The goal is to find where in the chi-squared space, the value of chi-squared increases by some threshold amount. I would recommend reading section 15.6 of Numerical Recipes by Press et al.
For example if you want 68% confidence intervals on all 3 parameters then you need to look along each parameter axis for where chi-squared increases by 3.53. If on the other hand you are only interested in $V$ then you look for values of $V$ that increase the chi-squared by 1 from its minimum value.
Note that most least-squares-fitters will also return the "covariance matrix" and the leading diagonal elements of this matrix are often used (very roughly) as the square of the 68% confidence error bar. I say roughly, because if the uncertainties are non-normal or if there is any dependence of one parameter on another (which there certainly is when you introduce $V$) then this approximation breaks down. Note that the above consideration is also why you cannot use the uncertainties in $A$ and $C$ to calculate errors in $V$ by standard error propagation formulae.
If uncertainties are really important to you then you probably need to do a Monte-Carlo simulation and adopt a Bayesian approach to estimating the posterior probability functions for the parameters. That is beyond the scope of a simple Physics SE answer.