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As Earth's precession is caused by the differential solar, etc., attraction to its 'spare tire', then does the rate go to ~zero at the equinoxes and ~twice the average at the solstices? (preferred answer: yes :-)

Or is there some 'carry-over' 'precessional momentum' that keeps the annual rate more constant? (preferred answer: no :-)

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The contribution to the precession from the sun does depend on the time of year (basically because tidal forces have a azimuthal symmetry around the line connecting the bodies but no polar symmetry), but there is also a contribution of similar magnitude from the moon, so the overall effect has a more complicated time dependence and only rarely drops to zero.

The inertia in the system is the angular momentum of the planet which will have a constant direction if there is no torque. Nor should you be imagining the tidal torque just disappearing, it rises and falls smoothly.

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  • $\begingroup$ thanks. But for an ideal two-body system with a circular orbit (I know, I know) would the rate go to zero at the equinoxes? $\endgroup$
    – user38715
    Commented Sep 6, 2017 at 20:04

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