Why a body can not be accelerated to speed of light in vacuum? [duplicate]

Question

Well i know that it needs infinite energy..but the term infinite is itself not physical so i am not satisfied with this answer ...but what would happen if we provide a constant acceleration to an object for hundreds of year ...isn't its velocity will go on increasing with time ?? some told me as velocity increases ...so time dilation occurs and time slows down ...so acceleration will not work ...but i didn't get it ..its all messed up ...please help ..

Can i get an answer only in term of forces and time i mean without using infinite energy concept ...i hope you will get what i wanna ask about

Answer 1

Well the kinetic energy of an object can be written as $$E=(\gamma-1)m_0c^2$$where $\gamma$ is the realativistic factor $$\gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}$$ $m_0$ is the rest mass and $c$ is the speed of light. From this you can see that $$\lim_{v\to c}\gamma=\infty$$ This means that the energy tends towards infinity as you get faster. Obviously we have no concept of infinite energy - and neither do we have to, as you can't reach the energy required to get to $c$.

Hope this helps :)

Answer 2

You have the answer in your own question. You only have to get rid of classical prejudices and understand that time is not universal anymore. Different observers do measure different time rates. If your velocity is higher, your time runs slower. For usual velocities this is never noted, but if you travel at really high $v$'s (e.g. 10% of c) you will start noting that. If you try to reach $c$, our time just freezes, so there's no next instant in which your velocity has increased over $c$.

Answer 3

if we provide a constant acceleration [...] answer only in term of forces

The problem is this "if": it can't be realized, you can't keep the acceleration constant.

You can keep the force constant, perhaps, but what you are going to observe then is that, even though the force is constant, the acceleration starts decreasing noticeably as you get close to light speed, tending to zero as the speed tends to $c$. So you never reach it.

The explanation of why that happens could be given in the lines of:

The (relativistic) mass $m$ of an object of (rest) mass $m_0$ (at $v=0$) grows with the speed $v$ according to $m = m_0/\sqrt{1-v^2/c^2}$, which clearly diverges for $v\to c$.

Notice, though, that that would be probably misleading, as it's nowadays pretty much agreed on, that "In reality, the increase of energy with velocity originates not in the object but in the geometric properties of spacetime itself." Nonetheless, it gives still probably a helpful intuition if someone wants to reason in terms of forces.

Answer 4

By acceleration, I assume you mean the 3-acceleration, the one that was learnt before relativity.

If the 3-acceleration is constant, the 3-velocity increases linearly, and the mass $m=m_0/\sqrt{1-v^2/c^2}$ increases, too. So the 3-force $F=ma$ is increasing linearly with the mass. So as you can see, as 3-velocity approaches $c$, the mass $m$ approaches infinity, so does the 3-force.

I hope this answers your question. It is difficult not to use the concept of "infinity".

Answer 5

The answer is as trivial as it could only be. To accelerate a body to a velocity greater the velocity of light $c$ you need a body or at least a system which is faster interacting with your body as $c$. As long as an interaction faster $c$ is not observed you won't have the "leverage" to accelerate something behind $c$.