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Which are the null components (in a Cartesian coordinate system) of the Electric field of uniformly charged plane in $x=0$?

I consider the coordinates : $(x,y,z)$
I think that $E_x = 0$, $E_y \ne 0$, $E_z = 0$


Is it correct?
Thanks!

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2 Answers 2

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Assuming y is perpendicular to the plane, you are correct, by symmetry you cannot have a preferred direction along the plane, so the electric field components must be zero

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The plane is an equipotential surface. Since the electric field is the (negative) gradient of the potential, the electric field can have no non-zero component parallel to the surface.

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