0
$\begingroup$

enter image description hereenter image description hereI was asked to draw a diagram of the forces acting on a ball in vertical circular motion when it is at a horizontal point.

I drew the weight of the ball acting straight down and the centripetal force acting horizontally towards the centre of the circle. The marking scheme included a third force the'reaction' acting vertically upwards. My questiong is where is this third force coming from? (I know it has velocity upwards but i don't see how this could be considered a force

$\endgroup$
4
  • $\begingroup$ Can you draw a diagram and add to this question? And be clearer in what the mark scheme shows? From your description here you are perfectly right in what you did - there is no such 3rd force unless the question is missing information. $\endgroup$
    – Steeven
    Commented May 30, 2016 at 22:32
  • $\begingroup$ By the way, what exactly is a "horizontal point"? $\endgroup$
    – Steeven
    Commented May 30, 2016 at 22:32
  • 1
    $\begingroup$ I added pictures of the question and marking scheme $\endgroup$
    – Robert S
    Commented May 30, 2016 at 22:36
  • $\begingroup$ The key point that you missed is the work "uniform" in describing the motion.With your free body diagram will the motion have constant speed or not? $\endgroup$ Commented May 30, 2016 at 22:45

1 Answer 1

0
$\begingroup$

The picture of the man shows it.

  • Was it a ball on a string, then only pulling in the string is possible - no lifting. Then only a force towards the center (the pulling force) and gravity are present.

  • In this case, though, the person clearly lifts the ball. He pushes it upwards. Therefor we have an upwards pushing force as well.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.