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I understand how the wave function is derived. I also understand how to check if a function serves as a solution to the wave equation:

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If a function is solution to this wave equation, what does this mean? Is the function a wave? How do I get an intuitive grasp on this? Essentially, when I look at a function, and see that it is a solution to the wave equation, what insights does it give me into what the function represents?

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  • $\begingroup$ Have a look at the answers here $\endgroup$
    – ACuriousMind
    Commented Mar 10, 2016 at 18:38
  • $\begingroup$ Agreed, but one point is buried under some details in that answer: any function of the form $y(x,t) = f(x-vt)$ is a solution of the wave equation. Any disturbance that moves with speed $v$. $\endgroup$
    – garyp
    Commented Mar 10, 2016 at 19:07
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    $\begingroup$ I am confused, is this the wawe equations? or $\dfrac{\partial^2 y}{\partial x^2}=\dfrac{1}{v^2}\dfrac{\partial^2 y}{\partial t^2}$ $\endgroup$ Commented Aug 17, 2018 at 15:01

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If a function is solution to this wave equation, what does this mean? Is the function a wave? How do I get an intuitive grasp on this? Essentially, when I look at a function, and see that it is a solution to the wave equation, what insights does it give me into what the function represents?

You are confusing mathematics with physics.

In physics wave are an observed effect in many frameworks, i.e. sinusoidal behavior. When searching for a mathematical model the relevant equation must have sinusoidal solutions. This does not mean that all solutions are realized in nature , they may be, and often are. But to call it a wave equation it is only necessary that it has sinusoidal solutions.

A wave is an observed behavior varying sinusoidally, so a non sinusoidal solution cannot be used to describe a physical wave. It might describe exponential decay , which is a different type of a physical observation than a physical wave.

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If you want a physical picture of what a solution to the wave equation is then you need to have a physical system in mind. Suppose we are talking about sound waves. Then the value of $y(x,t)$ is a displacement of the density of air from equilibrium $$\rho(x,t)=\rho_0+y(x,t)$$ at position $x$ and time $t$. For the sake of building intuition consider a very simple solution $$y(x,t)=y_0\sin(k(x-vt))$$ Note that the only parameter that comes from the wave equation is $v$. If we set $t=0$ then even $v$ is gone and the function now has nothing to do with the wave equation $$y(x,0)=y_0\sin(kx)$$ To get information from the wave equation we have to supply an initial condition, i.e., we have to put in $y_0$ and $k$ based on measurements of the density at a given time. For instance we might find the following density profile at time $t=0$

enter image description here

If we can supply these parameters then the wave equation tells us how the system evolves with time. We can predict what the density will be at a later time (or a previous times) like in this figure

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So you see the density does not stay fixed if it is disturbed. The valleys in the density move to the right as time progresses.

In general the density will not be a simple sine wave. If we measure the density at time $t=0$ and find that it is described by some complicated function with $$y(x,0)=f(x)$$ then we can just use the form garyp suggested, i.e., $$y(x,t)=f(x-vt)$$ $$\rho(x,t)=\rho_0+f(x-vt)$$ and you can check that $y(x,t)=f(x-vt)$ satisfies the wave equation for any function $f$.

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  • $\begingroup$ I can't help but notice that aside from sine and cosine functions, exponential functions e^a(x-vt) seem to be eigen solution of the wave equation... but it doesn't seem to make sense to me... AM I wrong on this? $\endgroup$ Commented Jul 13, 2016 at 0:36
  • $\begingroup$ @vtd-xml-author it is called a wave equation because it has sinusoidal solutions which can be used to fit observations physics sees as "waves". This does not exclude other solutions. It is not the solutions that create the waves, they are sought in order to fit physical wave behavior. $\endgroup$
    – anna v
    Commented Mar 6, 2017 at 6:41

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