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A number of times I have encountered in text-books and articles that neutrinos might contribute only a small fraction to dark matter. The reason has to do with the fact that if all of the dark matter consisted of neutrinos, then small-scale structures in the Universe could not have formed yet, because, as they say, neutrinos "wash out" small fluctuations. However, none of these texts provided a reference to any specific sources explaining in detail what is meant by "washing out". After all, neutrinos are notorious in their weak interaction with baryonic matter, so if there is a small-scale fluctuation of baryons, then how background neutrinos can prevent it from growing further if they practically do not interact with baryons? I guess the question boils down to calculating cross-sections of interactions at specific temperatures. I would appreciate comments and references to sources addressing this particular issue.

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  • $\begingroup$ Maybe someone has the expertise to answer this fully but my intuition is based on the two following facts 1) the main interaction is gravitational and in that respect the dark matter plays a major role in the structure formation 2) neutrinos are very light and they need only very small excitations to escape gravitational wells. Combining 1) and 2) gives you that the structures formed by neutrinos should be very diffuse or perhaps even "washed-out". $\endgroup$
    – Void
    Commented Jan 8, 2015 at 16:26
  • $\begingroup$ Yes, I understand that structure in the neutrino background itself should be diffuse and washed out. What I fail to grasp is how neutrinos wash out structures of baryonic matter. $\endgroup$
    – ThisGuy
    Commented Jan 8, 2015 at 16:32
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    $\begingroup$ Possible duplicates: physics.stackexchange.com/q/17227/2451 and links therein. $\endgroup$
    – Qmechanic
    Commented Jan 8, 2015 at 16:53
  • $\begingroup$ @Qmechanic this question specifically asks (and focuses on) why neutrinos would wash out small fluctuations. As such, the answers to that question would not be sufficient for this one and vice versa $\endgroup$
    – Jim
    Commented Jan 8, 2015 at 16:58

2 Answers 2

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We know matter started out evenly spread, because the cosmic microwave background is extraordinarily homogeneous. And yet we know the first galaxies were forming barely half a billion years after the Big Bang. So the aggregation of matter to form large gravitational structures was extraordinarily quick.

It's relatively straightforward to model how fast the perturbations seen in the CMB would have grown, putting in various conditions like the density of matter, and generally speaking if we start with cold dark matter the growth rate is fast enough. NB visible matter wouldn't have been able to create galaxies so fast on its own because its density simply isn't great enough. The galaxies formed so fast because the much higher density dark matter was able to form gravitationally bound structures and the baryonic matter followed it into the wells.

However in the big bang neutrinos were created with relativistic velocities, and it's exceedingly difficult to form gravitationally bound structures from fast moving objects. The velocity of the objects will always be far above the local escape velocities. If all dark matter were neutrinos it would take an enormous time to form gravitationally bound structures because it's exceedingly hard for neutrinos to lose their energy and slow down enough.

And this is why the dark matter can't be neutrinos. It isn't that the neutrinos in some way stop baryonic matter from forming gravitationally bound structures, but rather that baryonic matter required help from dark matter to form those structures fast enough. Neutrinos could not have provided that help.

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  • $\begingroup$ "visible matter wouldn't have been able to create galaxies so fast on its own because its density simply isn't great enough". Ok, but if there is a relativistic background (hot dark matter) of sufficiently high density - wouldn't it accelerate the gravitational dynamics of the baryonics matter embedded into this background? $\endgroup$
    – ThisGuy
    Commented Jan 8, 2015 at 17:15
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    $\begingroup$ @ThisGuy A uniform background density provides no additional gravitational force because you have an equal amount of gravity sources on all sides. There is a net cancelling effect. To have any effect, there needs to be perturbations in the background $\endgroup$
    – Jim
    Commented Jan 8, 2015 at 17:35
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    $\begingroup$ @ThisGuy: yes you're wrong. In a smooth background the matter distribution about any point is isotropic and homogenenous, so the gravitational force at that point cancels to zero. Your hypothetical test particle would feel just the gravitational force due to the mass $M$ and none due to the background. $\endgroup$ Commented Jan 8, 2015 at 18:04
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    $\begingroup$ Why do big-bang origin neutrinos have to be relativistic? $\endgroup$
    – Joshua
    Commented Jan 8, 2015 at 21:07
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    $\begingroup$ @Joshua Because they are hot, weakly interacting particles with very low mass. No doubt there was at least one neutrino with a low velocity, but they in general had every reason to be going fast and no reason to be going slow $\endgroup$
    – Jim
    Commented Jan 8, 2015 at 21:26
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The dark matter energy density of the universe is, at present, thought to be about five times that of the baryonic matter energy density. Meanwhile, the radiation energy density is almost negligible. Matter energy is about 4.5% of the total energy density of the universe. Dark matter makes up about 23%, and radiation is very small at about 0.009%. The number for radiation was calculated including all relativistic particles, including neutrinos. In fact, if you go through and read this link, it details the calculation for the total neutrino energy density and shows that it is thought to be about 68% of the photon energy density. So the 0.009% of the universe that is relativistic particles is not even mostly neutrinos.

My point? There truly is simply not enough neutrinos out there to explain away dark matter as neutrinos. Not only that, but we have clearly already included them in the calculation. Dark matter makes up 22.7% (give or take) of the energy density of the universe. And that is on top of the less than 0.0036% that neutrinos account for. So there's no way that neutrinos could be a major, let alone sole, component of dark matter.

For an overview of the energy densities, see Wikipedia and links therein

To answer your question on "washing out", the Wikipedia article on Dark Matter does a very good job at explaining this. For small scale structure to form, dark matter is required to help gravitationally bind baryonic matter. However, the free streaming length of any candidate particle that accomplishes this must be small. The free streaming length is the distance that the particles move in the early universe from random motions before the expansion slows them down. Primordial density fluctuations provide the seeds for small scale structure to form, but if the free streaming length of the dark matter candidate particle is larger than the scale of the small primordial perturbations, then these perturbations become homogenized (or "washed out") as the particles communicate and equilibrate. Without the perturbations, there is no seed for the small scale structure and, thus, it does not form.

Now you may be wondering why dark matter is needed in the first place for small scale structure to form. After the Big Bang, ordinary baryonic matter had too much temperature and pressure to collapse into structure on its own. It requires a gravitational seed (like giving it a kick-start to get the gravitational collapse going), which means there has to be a perturbation in the density of a colder, less interacting form of matter to provide this seed; that is, a local density of this cold dark matter that is higher than the background value. These perturbations would be formed because of the primordial density perturbations left over from inflation. However, neutrinos are known to have a high free streaming length, thus they would smooth out these perturbations in their own density and you wouldn't get a local high density region that could act as a seed. No seed means no collapse. No collapse means no small scale structure (until it's much too late). Neutrinos are actually the primary candidate for hot dark matter, but they are not a viable consideration for cold dark matter, which is what is necessary to generate sufficient small scale structure formation.

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  • $\begingroup$ I downvoted v1, because 1) neutrinos are nowadays non-relativistic 2) You quote $\Lambda-\rm CDM$ fits but those work with a non-relativistic cold dark matter from the very beginning 3) You do not answer the "wash-out" part of the question and structure formation at all. $\endgroup$
    – Void
    Commented Jan 8, 2015 at 16:30
  • $\begingroup$ @Void I hope this is more satisfactory $\endgroup$
    – Jim
    Commented Jan 8, 2015 at 16:56
  • $\begingroup$ I still see no answer to my specific question. Quote: "if the free streaming length of the dark matter candidate particle is larger than the scale of the small primordial perturbations, then these perturbations become homogenized (or "washed out") as the particles communicate and equilibrate". But this is exactly what I am asking :) I cannot grasp how neutrinos can communicate and equilibrate with baryonic matter. $\endgroup$
    – ThisGuy
    Commented Jan 8, 2015 at 17:07
  • $\begingroup$ @ThisGuy This should address the source of the confusion $\endgroup$
    – Jim
    Commented Jan 8, 2015 at 17:26
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    $\begingroup$ This answer might be slightly improved by being specific that it refers to know neutrino flavors, and that there is still speculation about possible heavy, sterile flavors as a possible dark matter component. $\endgroup$ Commented Sep 2, 2015 at 3:26

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