3
$\begingroup$

The equation for radiative transfer is $$ \omega \cdot \nabla I = \kappa(B - I) $$ where $I$ is the intensity of radiation, $\omega$ is the ray direction, $\kappa$ the absorption coefficient, $B$ the Planck function. Here, $\kappa=\kappa(\nu)$ (i.e., it depends on the radiation frequency $\nu$).

Often, though, the gray model, where $\kappa$ doesn't depend on $\nu$, is used. How can this be justified? What assumptions are used to obtain the gray model from the non-gray model?

$\endgroup$
1
  • 3
    $\begingroup$ I've modified your question to be more clear in hopes to reopen it. I believe that I kept the intent of your question in tact, but please check this so that we are answering the question you want answered. $\endgroup$
    – Kyle Kanos
    Commented Jul 7, 2014 at 2:38

1 Answer 1

2
$\begingroup$

The gray model results from starting with the assumption that we have a plane-parallel slab:

enter image description here

The light ray from the source (i.e., the star's atmosphere) travels at some angle, $\theta$, from normal, $z=0$. Since the light is coming from an angle, we need to account for that by modifying the radiative transfer equation to have a vertical optical depth, defined by $$ \tau_{\lambda,v}(z)=\int_z^0\kappa_\lambda\rho\,dz $$ which gives us $$ \omega\frac{dI_\lambda}{d\tau_{\lambda,v}}=I_\lambda-B_\lambda $$ with $\omega=\cos\theta$. Since the path length of the ray does not offer a unique geometric depth of the atmosphere, we cannot use $\nabla I$ and must use the above form for the radiative transfer equation.

In most stellar atmospheres, the primary source of opacity is the photoionization of H$^-$ ions. Fortunately, the opacity from photoionzation of hydrogen ions does not vary rapidly with wavelength, so we can approximate the opacity as $$ \kappa_\lambda\approx \bar\kappa $$ where $\bar\kappa$ is some average opacity, usually the Rosseland mean opacity.

$\endgroup$
2
  • $\begingroup$ How to justify the using of the gray model if, for example, some combustion system is considered but not atmosphere processes? The absorption coefficient may oscillate among spectral lines. $\endgroup$
    – jokersobak
    Commented Jul 8, 2014 at 5:08
  • 2
    $\begingroup$ If the opacity does vary a lot with wavelength, then you cannot use the gray model as an accurate representation. I would think, though, that it still would be good for a first-order model. $\endgroup$
    – Kyle Kanos
    Commented Jul 8, 2014 at 10:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.