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Bumped by Community user

In the following circuit involving a potentiometer;

enter image description here

Assume V$V$ to be the voltage produced by the cell in the primary circuit across the length AJ$AJ$ of the potentiometer wire, and E$E$ to be that produced by the cell of the secondary circuit.

In the case of V=E$V=E$, it's known that there is zero current through the secondary circuit. The current would obviously follow the path of the potential drop and not the rise, but in this limiting case, why is there current flow through the potentiometer wire instead of the secondary circuit, when the potential drops are similar in both?

In the following circuit involving a potentiometer;

enter image description here

Assume V to be the voltage produced by the cell in the primary circuit across the length AJ of the potentiometer wire, and E to be that produced by the cell of the secondary circuit.

In the case of V=E, it's known that there is zero current through the secondary circuit. The current would obviously follow the path of the potential drop and not the rise, but in this limiting case, why is there current flow through the potentiometer wire instead of the secondary circuit, when the potential drops are similar in both?

In the following circuit involving a potentiometer;

enter image description here

Assume $V$ to be the voltage produced by the cell in the primary circuit across the length $AJ$ of the potentiometer wire, and $E$ to be that produced by the cell of the secondary circuit.

In the case of $V=E$, it's known that there is zero current through the secondary circuit. The current would obviously follow the path of the potential drop and not the rise, but in this limiting case, why is there current flow through the potentiometer wire instead of the secondary circuit, when the potential drops are similar in both?

Fixed obvious theoretical mistakes
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harry
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In the following circuit involving a potentiometer;

enter image description here

Assume V to be the voltage produced by the cell in the primary circuit across the length AJ of the potentiometer wire, and E to be that produced by the cell of the secondary circuit.

In the case of V=E, it's known that there is zero current through the secondary circuit. Here,The current would obviously follow the netpath of the potential difference between Adrop and J is zeronot the rise, but in this limiting case, why is there current still flowsflow through the potentiometer wire.

How does this occur? If instead of the potentials at A and J are equalsecondary circuit, shouldn't there be no current flowwhen the potential drops are similar in both?

In the following circuit involving a potentiometer;

enter image description here

Assume V to be the voltage produced by the cell in the primary circuit across the length AJ of the potentiometer wire, and E to be that produced by the cell of the secondary circuit.

In the case of V=E, it's known that there is zero current through the secondary circuit. Here, the net potential difference between A and J is zero, but current still flows through the potentiometer wire.

How does this occur? If the potentials at A and J are equal, shouldn't there be no current flow?

In the following circuit involving a potentiometer;

enter image description here

Assume V to be the voltage produced by the cell in the primary circuit across the length AJ of the potentiometer wire, and E to be that produced by the cell of the secondary circuit.

In the case of V=E, it's known that there is zero current through the secondary circuit. The current would obviously follow the path of the potential drop and not the rise, but in this limiting case, why is there current flow through the potentiometer wire instead of the secondary circuit, when the potential drops are similar in both?

Source Link
harry
  • 256
  • 2
  • 20

Current flow in potentiometers

In the following circuit involving a potentiometer;

enter image description here

Assume V to be the voltage produced by the cell in the primary circuit across the length AJ of the potentiometer wire, and E to be that produced by the cell of the secondary circuit.

In the case of V=E, it's known that there is zero current through the secondary circuit. Here, the net potential difference between A and J is zero, but current still flows through the potentiometer wire.

How does this occur? If the potentials at A and J are equal, shouldn't there be no current flow?