Skip to main content
edited tags
Link
Cosmas Zachos
  • 66.3k
  • 6
  • 110
  • 248
Tweeted twitter.com/StackPhysics/status/1268558164351467521
edited tags
Source Link
Qmechanic
  • 212.7k
  • 48
  • 589
  • 2.3k

According to the Particle Data Group, the lifetimes of the neutral and charged $\Xi$ baryons$\Xi$ baryons differ significantly: $\tau(\Xi^-) = (1.639 \pm 0.015) \times 10^{-10}$ s, while $\tau(\Xi^0) = (2.90 \pm 0.09) \times 10^{-10}$ s. This is despite the fact that the dominant decay mode of both is to $\Lambda \pi$ (with a charged or a neutral pion, respectively), and both decays proceed through the same quark-level transition.

What is the reason why the neutral $\Xi$ lives almost by a factor 2 longer? Is there a simple explanation, or the answer is hidden in non-perturbative QCD effects?

According to the Particle Data Group, the lifetimes of the neutral and charged $\Xi$ baryons differ significantly: $\tau(\Xi^-) = (1.639 \pm 0.015) \times 10^{-10}$ s, while $\tau(\Xi^0) = (2.90 \pm 0.09) \times 10^{-10}$ s. This is despite the fact that the dominant decay mode of both is to $\Lambda \pi$ (with a charged or a neutral pion, respectively), and both decays proceed through the same quark-level transition.

What is the reason why the neutral $\Xi$ lives almost by a factor 2 longer? Is there a simple explanation, or the answer is hidden in non-perturbative QCD effects?

According to the Particle Data Group, the lifetimes of the neutral and charged $\Xi$ baryons differ significantly: $\tau(\Xi^-) = (1.639 \pm 0.015) \times 10^{-10}$ s, while $\tau(\Xi^0) = (2.90 \pm 0.09) \times 10^{-10}$ s. This is despite the fact that the dominant decay mode of both is to $\Lambda \pi$ (with a charged or a neutral pion, respectively), and both decays proceed through the same quark-level transition.

What is the reason why the neutral $\Xi$ lives almost by a factor 2 longer? Is there a simple explanation, or the answer is hidden in non-perturbative QCD effects?

Source Link
Martino
  • 988
  • 5
  • 14

Why are the lifetimes of the neutral and charged $\Xi$ hyperons so different?

According to the Particle Data Group, the lifetimes of the neutral and charged $\Xi$ baryons differ significantly: $\tau(\Xi^-) = (1.639 \pm 0.015) \times 10^{-10}$ s, while $\tau(\Xi^0) = (2.90 \pm 0.09) \times 10^{-10}$ s. This is despite the fact that the dominant decay mode of both is to $\Lambda \pi$ (with a charged or a neutral pion, respectively), and both decays proceed through the same quark-level transition.

What is the reason why the neutral $\Xi$ lives almost by a factor 2 longer? Is there a simple explanation, or the answer is hidden in non-perturbative QCD effects?