From the linear velocity function in Equation 2-11, the average velocity over any time interval (say, from $t=0$ to a later time $t$) is the average of the velocity at the beginning of the interval ($=v_0$) and the velocity at the end of the interval ($=v$). For the interval from $t=0$ to the later time $t$ then, the average velocity is $$v_{\mathrm{avg}} =\frac{1}{2} (v_0+v)$$

I don't understand why average velocity can be found just be taking the mean of 2 velocities. Can someone please explain?

From the linear velocity function in Equation 2-11, the average velocity over any time interval (say, from $t=0$ to a later time $t$) is the average of the velocity at the beginning of the interval ($=v_0$) and the velocity at the end of the interval ($=v$). For the interval from $t=0$ to the later time $t$ then, the average velocity is $$v_{\mathrm{avg}} =\frac{1}{2} (v_0+v)$$

I don't understand why average velocity can be found just be taking the mean of two velocities. Can someone please explain?

I don't understand why average velocity can be found just be taking the mean of 2 velocities. Can someone please explain?

From the linear velocity function in Equation 2-11, the average velocity over any time interval (say, from $t=0$ to a later time $t$) is the average of the velocity at the beginning of the interval ($=v_0$) and the velocity at the end of the interval ($=v$). For the interval from $t=0$ to the later time $t$ then, the average velocity is $$v_{\mathrm{avg}} =\frac{1}{2} (v_0+v)$$

I don't understand why average velocity can be found just be taking the mean of 2 velocities. Can someone please explain?