Timeline for Will the Sun ever get 100x powerful? If so, when?
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 13, 2015 at 2:53 | vote | accept | Damodar Dahal | ||
| Oct 12, 2015 at 16:01 | answer | added | ProfRob | timeline score: 5 | |
| Oct 12, 2015 at 15:21 | vote | accept | Damodar Dahal | ||
| Oct 13, 2015 at 2:53 | |||||
| Oct 12, 2015 at 15:07 | comment | added | Michael Seifert | @KyleKanos: fair enough. If the OP wants a better first-order approximation (second-order approximation?), they could treat $T$ as constant and see how big $R$ needs to be to get the right luminosity. | |
| Oct 12, 2015 at 14:58 | comment | added | Kyle Kanos | @MichaelSeifert: I know, that's why I posted it as a comment (with the mention of first order approximation, which may even be an over-shoot) and not an answer. OP's best bet would be to do full evolutionary calculations. | |
| Oct 12, 2015 at 14:45 | comment | added | Michael Seifert | @KyleKanos: The problem with that idea is that the Sun's temperature never actually rises significantly. The Sun will actually get up to the desired luminosity as a red giant, but by that time its surface temperature has actually gone down; the extra power output is actually more closely related to its larger radius (and surface area) instead. | |
| Oct 12, 2015 at 14:40 | answer | added | Michael Seifert | timeline score: 3 | |
| Oct 12, 2015 at 14:22 | comment | added | Kyle Kanos | @Physicist137: Yeah, it's not particularly useful on its own. However, it'd give OP a temperature needed for the output which can be used to see what burning cycle is needed. Age estimates for each cycle can be found in abundance elsewhere (online & textbooks). | |
| Oct 12, 2015 at 14:12 | comment | added | Physicist137 | @KyleKanos Since your comment is after the edit, I have a question: How is this going to help to know when the sun will get 100x more power? | |
| Oct 12, 2015 at 13:53 | comment | added | Kyle Kanos | Assume that $R={\rm const}$ and figure out how much hotter the temperature has to be such that $P_\star=100P_{\odot,now}$, that'd give you a first-order approximation. | |
| Oct 12, 2015 at 13:45 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
Changed title so it does not depend on unproven assumptions.
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| Oct 12, 2015 at 13:39 | history | edited | Kyle Kanos | CC BY-SA 3.0 |
tag swap, added image & equation, etc
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| Oct 12, 2015 at 13:31 | review | First posts | |||
| Oct 12, 2015 at 13:44 | |||||
| Oct 12, 2015 at 13:28 | history | asked | Damodar Dahal | CC BY-SA 3.0 |