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Just to connect the dots: You can take an POVM defined by a set of positive operators $\{E_i\}$ and then define Kraus operators $K_i = E_i^{1/2}$, where "1/2" denotes the unique positive square root of a positive operator. These Kraus operators define the channel.
Thanks for the thoughtful reply. The application we have in mind is proving a general $\hbar\to 0$ limit of the Lindblad equation in quantum mechanics; we are specifically trying to be as general as possible. I think the problem in the case of no boundary and C^k functions is already quite interesting and broadly applicable, and indeed I would characterize non-C^2 functions as unphysical exceptions.
Is there a modern self-contained treatment? Everyone cites the Pfeuty and Lieb-Schultz-Mattis papers, but LSM just introduced the method, applied to different models, and Pfeuty just cites LSM for the method and basically writes down the answer without many details.
@Thriveth The effective range of electromagnetism is limited by the net-zero charge density. There's a 1/r^2 law for isolated charges, but it falls off faster for net-zero charge distribution (e.g., 1/r^3 for the dipole moment, or even faster for higher moments). This is "screening", and it means effective finite range. But gravity is unscreened because there's no negative mass.
@knzhou Sorry, you're right, I absolutely should have written "'local' conserved quantities", with quotes around 'local' to emphasize that the appropriate notion of locality is unclear (e.g., finite spatial radius vs quasi-local spatial decay.). You may also be interested in Dan Ranard's observation that the projectors $O_i=|i\rangle\langle i|$ are linearly independent but not algebraically/functionally independent.
Expanding on SuperCiocia's comment, one might say a quantum lattice system is "partially integrable" if it has an extensive number of conserved quantities that are independent in the appropriate sense and "fully integrable" if their simultaneous eigenspaces are 1-dimensional and hence give a full orthonormal basis of labeled states for the Hilbert space.
If we trivially extend a Kadison map to all Hermitian operators using $\rho' = \mathrm{Tr}[\rho_+](\rho_+/\mathrm{Tr}[\rho_+])' - \mathrm{Tr}[\rho_-](\rho_-/\mathrm{Tr}[\rho_-])'$, where $\rho_\pm$ are the positive and negative parts of $\rho$, then is the condition that the map "preserves the convex structure" equivalent to saying the map is linear? If so, then a Kadison map is just a bijective positive trace-preserving (PTP) map, right? And then Kadison's theorem is the statement that the only bijective PTP maps are unitary? (Maybe some of that breaks down in finite dimensions?)
What I think is going on is that some fluid properties of helium-4 (which I don't understand) sets a characteristic length scale much smaller than 1 mm, and that within each region of that size roughly 7% of the atoms are in the same mode of that size. Indeed, the "characteristic lambda transition temperature" for superfluid helium-4 is a relatively balmy 2.17 Kelvin. Need an expert to comment.
If the real-life experiments were like the textbook example, then I'd agree with you that the 7% component would all be in a single mode. However, if you have a macroscopic amount of superfluid helium-4, say in a 1 mm square well, then the ground state temperature would be 10^-18 Kelvin. In contrast, the coldest lab temp ever is 10^-11 Kelvin (PRL)