Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
In case of external force, the force sums up to zero after taking the pseudo forces into the account since you are on a non inertial frame of reference.
yes once you go further from the charge and cross that point moving towards infinity (not at infinity though), then with reference to that point, since it's not at infinity, the potential will be negative. So graph won't be valid. But by convention, we always consider infinity as reference point. even for an atom, if an electron is outside atom, it is considered infinity and it's energy there is considered zero though it always decreases as it comes closer to the atom. Thus, as science students, this will be how we will interpret potential.
@ad2004 I agree but for infinite current, the potential difference through the shunt path will be given by Ir. Now, I is infinity anyways and r is 0. Then, V = ir = ∞. 0 which is undefined though it tends towards 1. Now what...
Yeah that's what I thought too. But theoretically speaking if we pass infinite current through the ammeter somehow, then will any current flow through the galvanometer in it?