Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Thank you for the answer, I will then ask my professor ehat he meant by that statement. He did, however, only say that for rigid bodies and rigid movement.
I don't understand why it wouldn't work, since this kinetic energy is not dependent on the direction of the velocity, it's a scalar: $W_k = \frac{1}{2}mv^2$. So if the rotational energy remains the same, then all other energies should go into this final kinetic energy. What is wrong with my way of thinking?