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The rate of change of velocity of a body per unit of time.
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Vertical motion of an object
We define acceleration as $-9.8\frac{m}{s^2}$ for an object that is thrown upwards due to gravity. … My question is when the object reaches maximum height at the point where it is about to turn around downwards, will the magnitude of the acceleration still be $9.8\frac{m}{s^2}$ or will it be greater than …