Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with conservation-laws
Search options not deleted
user 137850
The statement that a property of a system does not change if the system is isolated.
0
votes
2
answers
225
views
How to understand continuity equation intuitively as Lorenz covariant?
As we know, it is natural that we derive the differential form of continuity equation
$${\frac {\partial \rho }{\partial t}}+\nabla \cdot \mathbf {j} =0$$
from the integral form, in the view of absolu …
- 15
0
votes
How to understand continuity equation intuitively as Lorenz covariant?
I think I have some thoughts on my question after thinking for a while. Still waiting for other illuminating discussions.
We cannot simply consider continuity equation as a general incompressible flow …
- 15
0
votes
1
answer
220
views
Why total derivative becomes partial when we use the differential form of continuity equation?
The integral form: $\frac{d q}{d t}+\oint_{S} \vec{j} \cdot d \vec{S}=0$
The differential form: ${\frac {\partial \rho }{\partial t}}+\nabla \cdot \vec{j} =0$
How to intuitively understand the change …
- 58.6k
1
vote
1
answer
1k
views
Why the continuity equation means constant densities of each fluid parcel?
As we know, the definition of material derivative of $\varphi$ is: $\frac{D\varphi}{Dt}\equiv \frac{\partial \varphi}{\partial t} + \mathbf{u}\cdot\nabla\varphi$. And the physical meaning of material …
- 12.2k