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Electrostatics is concerned with the electrical fields and scalar potentials of stationary electrical charges and charge distributions. Use this for questions about electromagnetic situations in which currents and magnetic fields are absent, otherwise use the [electromagnetism] and/or [magnetic-fields] tags.

0 votes
1 answer
372 views

Electric potential of surface and volume charges?

The definition of electric potential is$$ \mathbf{V(r)}=-\int_C \mathbf{E}\cdot \, d\mathbf{l}$$ Is this formula only for line charges? What is the corresponding formulas for electric potentials of su …
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2 votes
1 answer
3k views

How to set up line integral of electric field? Confused over notation

In multivariable calculus the line integrals was parameterized and denoted: $$ \int_C \mathbf{F} \bullet \, d\mathbf{r}=\int_D\mathbf{F}(\mathbf{r}(t)) \bullet \frac{d \mathbf{r}(t)}{dt} \, dt $$ How …
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  • 443
1 vote
2 answers
3k views

Line integral of electric potential, how to set up?

I having a problem with the line integral of electric potential. I have a cylinder of radius $a$ and length $L$ with a uniformly surface charge. At point $b$ the potential is zero. I want to calculate …
JDoeDoe's user avatar
  • 443
7 votes
2 answers
5k views

Find electric potential due to line charge distribution?

I need help how to set up this integral $$V(\mathbf r)=\frac{1}{4\pi\epsilon_0} \int_L \frac{\rho'_l}{\lvert \mathbf r - \mathbf{r'} \rvert}\mathrm{d}l'. $$ I have a uniform line charge along the $z …
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1 vote
2 answers
1k views

Is the electric force a vector or a vector field?

The electric force (Coulomb's law) on a point charge $Q_2$ due to $Q_2$: \begin{gather*} \mathbf{F}_{12}=\frac{Q_1Q_2}{4\pi\epsilon_0}\frac{\mathbf{r}_2-\mathbf{r}_1}{|\mathbf{r}_2-\mathbf{r}_1|^3} \e …
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  • 443
0 votes
1 answer
655 views

The position vector $\mathbf{r}$ in the electric field?

I often see the electric field denoted \begin{align}\mathbf{E}(\mathbf{r})=E_x(\mathbf{r})\mathbf{\hat e}_x+E_y(\mathbf{r})\mathbf{\hat e}_y+E_z(\mathbf{r})\mathbf{\hat{e}}_z=(E_x(\mathbf{r}),E_y(\mat …
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1 vote
0 answers
40 views

Is the force in Coulomb's law a vector field? [duplicate]

In the definition of the electric field we have a vector field and a force. The vector field $\mathbf{E}(\mathbf{r})$ is a function of $\mathbf{r}$. What about the force, is it a vector $\mathbf{F}$ …
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