Assuming a very high energy photon (energy $E$) crosses the atmosphere and produces an electron-positron pair, I would like to know what is the angle between these to leptons produced. I was trying to calculate it by applying the energy-momentum conservation and realized that in this case the angle could be 0 if the momentum $p$ does not need to be conserved.

Question: Does $p$ need to be conserved in the interaction or is it enough that the following relation applies:$$ E^2=2\left(p_\text{e}c\right)^2+2\left(m_\text{e}c^2\right)^2 \,,$$where $p_\text{e}$ is the momentum of the resulting electron/positron and $m_\text{e}$ its mass?