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Why does the answer here use $ \Delta S=Q/T$ even though this isn’t reversible? [closed]
This question for my thermodynamics course ends up using $\Delta S = Q_{\text{waste}} / T,$ but I was taught that $ \Delta S=Q/T$ is only valid if the process is reversible. The question makes it ...
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How is a irreversible process (conventionally) represented on a $T-S$ plane and why cannot it be (really) represented?
A reversible process can be represented on a $T-S$ plane, and the area under the curve is the heat exchanged by the system.
On $P-V$ plane a irreversible process is conventionally represented with a ...
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