All Questions
4 questions
-2
votes
2
answers
122
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Why does $\vec{a}=\vec{\omega}\times \vec{r}$ as well as the velocity does?
Today I came in class and in one of the problems the teacher used $\vec{a}=\vec{\omega}\times \vec{r}$ which made me very confused because I don't know where it comes from, it seems pulled out of thin ...
3
votes
3
answers
653
views
Confusion about successive derivatives of position in circular motion
Suppose we define a unit vector $\vec r$ along radial direction for a particle in uniform circular motion at an angular frequency $\omega$. Then we can write:
$$\vec r = \cos(\omega t)\hat i + \sin(\...
-1
votes
1
answer
106
views
Radius as a constant while deriving of formula for acceleration in circular motion [closed]
While deriving acceleration in circular motion, we differentiate $\vec{v}=\vec{\omega}\times\vec{r}$
Here we differentiate by product rule and write $\frac{dr}{dt}$ as $v$.
So we know $\vec{s} =\vec{\...
0
votes
1
answer
2k
views
Derivation of centripetal acceleration
While reading HC Verma chapter 7 circular motion I came across a derivation which I couldnt understand. I have marked my doubt with red. I don't understand from where +dw/dt [- i sine +j cos0] came ...