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Is 4-velocity a Vector in the Sense of Covariant Derivative along Worldline

The definition of 4-velocity $U^{\mu} \equiv dx^{\mu}(\tau)/d\tau$, however, we've learnt that the covariant derivative for a vector along a curve parametrized by proper time is, $$\frac{DA^{\mu}}{D\...
Ting-Kai Hsu's user avatar
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1 answer
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Isomorphism of the tangent space and the space of directional derivatives [closed]

I have already constructed the tangent space to a manifold, denoted $T_pM$, and I have a good basis for it $\{\hat e_{(\mu)}\}$. (I followed the method of equivalence classes of curves tangent at $p$....
hodop smith's user avatar
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0 answers
103 views

Conceptual confusion about the formula for parallel transport

I am examining the covariant derivative of a vector according to the formula $$\nabla_{\mu}V^{\nu} = \partial_{\mu}V^{\nu} + \Gamma^{\nu}_{\mu \lambda}V^{\lambda}$$ and also operating under the ...
Relativisticcucumber's user avatar
1 vote
2 answers
143 views

Gradient of scalar field

On page183 of Rayd'inverno "An introduction to relativity" he says that the right term in parenthesis is a gradient of some scalar field i.e. When $$\partial_a (\frac{\ X_b}{\ X^2})=\...
Keshav Shrestha's user avatar
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1 answer
2k views

Derivative of a metric tensor

I would like to ask you a question - maybe simple - but bothering me. We have two four-position vectors product in curvilinear coordinates given by $(1) \quad X^{\alpha}g_{\alpha \beta}X^{\beta} = \...
pog's user avatar
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1 vote
0 answers
66 views

Differentiating the four-velocity contracted with itself

Let us denote $u^\mu$ as the contravarient component of a four velocity at a point in some coordinate system for a pseudo-Riemannian manifold. I want to examine the following equation. $$\partial_\nu(...
Nugi's user avatar
  • 551
0 votes
1 answer
197 views

4-velocity lowering index question

The 4-velocity in contravariant form is given by $$V^\mu=\frac{dx^\mu}{d\tau}$$ for some general co-ordinates $x^\mu$ and proper time $\tau$. Is the 4-velocity in covariant form given by $$V_\nu=V^\...
John Eastmond's user avatar
5 votes
2 answers
2k views

Why the unit vector is represented as a partial derivative in GR?

Can someone give a good intuitive explanation why we represent the unit vector as a partial derivative in GR and what does it mean?
Noam Chai's user avatar
  • 605
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2 answers
471 views

Why exactly in general relativity are tangent vectors defined as maps from functions to $\mathbb{R}$?

I am basing this on the lectures from the hereaus international winter school on gravity and light. If $M$ is the manifold of physical spacetime, then at any point $p \in M$, we have a tangent space ...
user56834's user avatar
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