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Meaning of colon symbol $:$ in optics

When I was reading some early days nonlinear optics paper/textbooks (particularly between 1960-1985), I often see expressions such as: $\chi^{(2)}:\textbf{E}\textbf{E}$ or $\nabla\textbf{E}:\partial \...
physstudent11's user avatar
0 votes
1 answer
132 views

Vector calculus in Electromagnetism [closed]

I found a problem which had $$\partial_i (A_j \vec{G})= (\vec{\nabla} .\vec{ A} )\vec{G}+ (\vec{A}.\nabla) \vec{G} $$ but my problem is what does $$\partial_i (A_j \vec{B})$$ even mean? it doesn't ...
SHIN101's user avatar
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4 votes
1 answer
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What does $\mathbf{A}\cdot\nabla$ mean here?

What does $\mathbf{A}\cdot\nabla$ mean in an expression like $(\mathbf{A}\cdot\nabla)\mathbf B$? I found this in Griffiths’ Classical Electrodynamics book and cannot figure it out.
Pranshu Khare's user avatar
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1 answer
1k views

Commutator of covariant derivative and field $F_{\mu \nu}$

I am working with the covariant derivative and trying to show that the commutator of this derivative $[D_\mu , D_\nu]$ is proportional to the field $F_{\mu \nu}$. That is, I need the final term to be ...
user avatar
1 vote
2 answers
812 views

Reason why dot notation isn't used for time derivatives in Maxwell's equations [closed]

Maxwell's equations seem to be usually written: \begin{align} \nabla \cdot \mathbf{E} &= \rho/\epsilon_0,\\ \nabla \cdot \mathbf{B} &= 0,\\ \nabla \times \mathbf{E} &= -\frac{\partial \...
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0 votes
1 answer
953 views

Derivative with tensor indices

I have trouble figuring out derivatives in tensor notation in SR. I haven't been able to find a simple recipe for writing down a solution. For example what would be the solution to the following ...
subgr0ph's user avatar
4 votes
2 answers
271 views

Conventions regarding partial derivatives

Look at this expression: $$\frac{\partial}{\partial t} (V-\mathbf{v}\cdot\mathbf{A}).$$ This expression occurs in Griffiths EM book (4th ed, p.444). $V=V(\mathbf{r},t)$is the scalar potential, $\...
kalkanistovinko's user avatar