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How to expand $(D_\mu\Phi)^\dagger(D^\mu\Phi)$ in $SU(2)$?

I would like to calculate the following expression: $$(D_\mu\Phi)^\dagger(D^\mu\Phi)$$ where $$D_\mu\Phi = (\partial_\mu-\frac{ig}{2}\tau^aA_\mu^a)\Phi$$ and $A_\mu^a$ are the components of a real $SU(...
Hendriksdf5's user avatar
0 votes
1 answer
111 views

Gauge covariant derivative for fields in tensor representations with multiple indices

In QFT, for fields transforming under some Gauge group, one defines the covariant derivative as $$ (1)\qquad D_{\mu} \phi = \partial_{\mu}\phi -igA_{\mu}^k \rho(t_k)_{ab}\phi_b $$ If $dim\rho=dim(\...
geodesic's user avatar
3 votes
0 answers
358 views

Integration by parts of covariant derivative

There already exists posts to discuss this question, but I don't think it's totally done! We can write the covariant derivative as $$D_i=\partial_i-igA_i^aT^a \tag{1}$$ There are two kinds of opinions ...
Daren's user avatar
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1 vote
2 answers
819 views

Showing the form of the covariant derivative of $\phi$, if $\phi$ transforms as the adjoint representation of $SU(n)$

I want to show that if $\phi$ transforms as the adjoint representation of SU(n), its covariant derivative is given by $\textbf{D}_\mu \phi = \partial_\mu \phi + i [\textbf{A}_\mu, \phi]$. (Exercise in ...
Slayer147's user avatar
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