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How much degree of freedom of a rigid body in $N$-dimensional space?

Well I have the answer it is $\frac{N(N+1)}{2}$ but what the procedure to derive it . I tried this. 1).I have $N$ number of translation freedom. To calculate the number of rotational freedom I tried ...
LEO PHYSICS's user avatar
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2 answers
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Locally accessible dimensions of configuration space

I am reading a book called "Structure and Interpretation of Classical Mechanics" by MIT Press.While discussing configuration space and degrees of freedom,the authors remark the following: Strictly ...
Sandesh Kalantre's user avatar