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-2 votes
1 answer
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Where did $1/2$ of this come from? [duplicate]

Work done by an external force $F$ upon a particle displacing from point 1 to point 2 is defined as $$ W_{12} = \int_1^2 F \cdot dr \, .$$ Kinetic energy and work-energy theorem: According to Newton's ...
arvind mannadey's user avatar
0 votes
3 answers
480 views

Goldstein: derivation of work-energy theorem

I am reading "Classical Mechanics-Third Edition; Herbert Goldstein, Charles P. Poole, John L. Safko" and in the first chapter I came across the work-energy theorem (paraphrased) as follows: ...
ananta's user avatar
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0 answers
145 views

Work-Energy Principle Derivation

I am currently in Mechanics I and both my professor and my book have derived the work principle in this way and I even asked about its derivation during class, but it has me puzzled. I don't ...
HappyHiggs's user avatar
2 votes
1 answer
87 views

How to express the elementary work definition as an explicit functional expression [duplicate]

My assumption here is that in the definition of elementary work : $dW = F ds$ symbol $d$ represents a differential. But a differential implies a function : $dy =_{df} d[f(x)] = f'(x) \Delta x = f'(...
Floridus Floridi's user avatar
1 vote
3 answers
1k views

Why is pressure assumed constant in the work equation? Doesn't pressure change with the change with volume unless isobaric?

Right now, I'm studying thermodynamics, and I am a bit confused on the differentials. For example, the equation for work is $W=p*{\Delta}V$, and usually people change it to $dW = p*dV$. But, as long ...
CuriousCat's user avatar
1 vote
0 answers
285 views

Why do they specify the differential of Work using an lowercase delta $\delta W$, instead of $dW$ [duplicate]

I was curious, why do they specify the differential of Work using an lowercase delta symbol $\delta$ as in "$\delta W$", instead of using a $d$, as in $dW$. For example: $$\delta W=\vec{F} ...
Bill Moore's user avatar