All Questions
10 questions
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2
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74
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If a ball experiences a force when it hits the ground, why can we still use the kinematic equations to solve for its freefall time?
Suppose a question states:
A ball is dropped from a height of 2m. Find the time it takes for which the ball is in free fall.
To solve this, we would plug in our known values into the kinematic ...
1
vote
5
answers
150
views
The value of $g$ in free fall motion on earth [closed]
When we release a heavy body from a height to earth. We get the value of $g=9.8 \ ms^{-2}$. Now, I'm confused about what it means. For example, does it mean that the body's speed increases to $9.8$ ...
0
votes
1
answer
90
views
An object falling from very far would have varying acceleration, how can that be accounted for?
I want to have a function that describes where a falling object is.
Like this one:
h(t) = -g*t²/2
But this one is for the usual close to the surface case, where there is no variation of gravity due to ...
0
votes
2
answers
68
views
Motion of free fall [duplicate]
We know that according to law of free falls object, all bodies fall with the same constant acceleration. But in distance formula ($s = \frac12 gt^2$), why the acceleration is just half?
1
vote
1
answer
38
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What numbers would I apply to the equation $y=y_o+v_ot+\frac 12at^2$ using this simulator?
Using a Projectile Motion Simulutator (selecting INTRO from the four choices), I set the height of the Cannon at $15 \ \text{m}$, Initial Speed = $8 \ \text{m/s}$, the bulls-eye at $13.9 \ \text{m}$. ...
1
vote
2
answers
107
views
Distance and velocity increased by $g$ units every second
Distance fallen in every second gets increased by $g$ units.
Velocity is increased by $g$ units every second.
Is it true that distance and velocity increases by $g$ after every second?
If it starts ...
-1
votes
1
answer
382
views
Why is the rate of change of velocity with distance not constant?
My physics textbook says, "Galileo concluded that the rate of change of velocity with time is a constant of motion for all objects in free fall. On the other hand, the change in velocity with ...
1
vote
4
answers
2k
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How can there be acceleration but no velocity at instant of maximum height when object projected upwards? [duplicate]
When we project an object vertically upwards its velocity at maximum height consider to be zero but still, it has acceleration due to gravity i.e $9.8\mathrm{m/s^2}$. But mathematically we know that ...
-1
votes
1
answer
238
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Use of direction of downward velocity in equation of motion
[NOTE: I am not asking anyone to solve the question below but to point out where I might be wrong]
Q- A skier jumps from a horizontal track and lands on a steeper track with a launch angle of ∅=11.3°(...
0
votes
2
answers
188
views
How does vertical deformation of an object soften the free fall of a body?
I'm a bit confused about the situation in this exercise:
A man fell off a building of height $h$, with null initial velocity, but he survived thanks to a metal box that softened the fall deforming ...