Question 2.11 from A First Course In General Relativity, 3rd Edition by Bernard Schutz, asks the reader to verify the following equation:
$$ \Lambda^\nu_\beta(v) \Lambda^\beta_\alpha(-v) = \delta^\nu_\alpha$$
After reintroducing the sums and iterating over $\beta$ we have:
\begin{align} & \sum\ \Lambda^\nu_\beta(v) \Lambda^\beta_\alpha(-v) \\[8pt] = {} & \Lambda^\nu_0(v) \Lambda^0_\alpha(-v) + \Lambda^\nu_1(v) \Lambda^1_\alpha(-v) + \Lambda^\nu_2(v) \Lambda^2_\alpha(-v) + \Lambda^\nu_3(v) \Lambda^3_\alpha(-v) \end{align}
I am only somewhat familiar with the Einstein Summation Convention at this point, so I am a little confused. Am I supposed to now sum each term over $\nu$ and $\alpha$? Since $\delta^\nu_\alpha$ is the Kronecker Delta clearly there is going to be a lot of cancellation, but I am not entirely sure how to move forward, and how do I tell the next step from the notation.
For reference I am teaching my self GR from this book, so I do not have reliable access to anyone fluent in GR. For this reason I want to be sure my understanding is sound before I move on.