The argument for Bremermann's limit, as I understand it, goes something like this:
Begin with the time-energy uncertainty principle, as
$\Delta E \Delta t \ge h$ (Other papers use other factors of $h$/$\hbar$, but Bremermann (1962) uses $h$, so let's stick with that.)
Substitute $\Delta E \le mc^2$ to get: $mc^2 \Delta t \ge h$, and rewrite as:
$1 / \Delta t \ge mc^2 / h$
Which sets a maximum limit on the clock rate of any physical process. You usually see this phrased as "The maximum computing rate is $1.36 \cdot 10^{50}$ bits per second per kilogram", and oftentimes this is phrased as the time it would take to e.g., strongly solve chess.
Is there a reason $\Delta E \le mc^2$? For instance, could we imagine $\psi = c_1 \psi_1 + c_2 \psi_2$ with $E_1 \approx 0$, $|c_2|^2 \ll 1$, and $E_2 \gg mc^2$? It seems this would satisfy $\langle H \rangle \le mc^2$ but leave $\langle H^2 \rangle - \langle H \rangle ^2$ unbounded.
Is such a state physically impossible (moreso than a computer that uses its entire mass-energy for computation constantly)? For a free particle, I can see that measuring the energy as $E_2 = p^2/2m > mc^2$ yields $p > mc$, which maybe suggests a velocity greater than $c$, but:
- Can you get around that with a potential $V \approx mc^2$?
- This is using non-relativistic QM for something in the relativistic domain. In non-quantum relativity, $p > mc$ is permitted, is that also true for the Dirac equation?