I have encountered some diagrams (like the example below) where two lines coming out of a single vertex (in this context, right-handed neutrino $N^c$) have opposite direction. In a usual diagram, a fermion propagator should have one direction only. Why is this different?
1 Answer
This propagator must come from Majorana fermion which satisfies the real condition i.e. there is only one kind of creation or annihilation operator in plane mode expansion: \begin{align} N^c=\int\overline{\mathrm{d}^3p}\left(e^{-ipx}\zeta a+e^{ipx}\eta a^{\dagger}\right)\, \end{align} where $\overline{\mathrm{d}^3k}$ is the one-particle covariant measure and $\zeta$ and $\eta $ are possible spinors which depend on representations.
As a consequence, $N^c$ could contract (Wick's contraction, recall that this contraction comes from $[a,a^\dagger]$) with $N^c$ itself, which generates this double arrow line.
But for Dirac fermion, there is only the contraction between $\psi$ and $\bar{\psi}$, which yields the one-way arrow from $\psi$ to $\bar{\psi}$ in the propagator.
There is the main difference between those two propagators in Feynman diagrams.