How do you calculate the energy transfer of sound to a certain area?

So imagine if you measure the sound intensity at a certain spot to be $$72$$ deciBels. If you look at the SI-units used in the ratio these are $$\text{W/m}^2$$. Does this mean that you can calculate the exact energy transfer per second on a given area, e.g. 2 cm2 to just be the amount of decibells you measure times the area including with the relative intensity?

I would like to calculate the energy transfer of sound.

The decibel (dB) is a unit for expressing the ratio between two sound intensities and so has no units.

One decibel equals $$10 \log_{10} \left (\dfrac{I_1}{I_2}\right )=20\log_{10} \left (\dfrac{P_1}{P_2}\right )$$, where $$I_1$$ and $$I_2$$ are the intensity of the two sounds and $$P_1$$ and $$P_2$$ are the corresponding amplitudes of the pressure waves.

Examples of sound pressure is a table which illustrates the use of the auditory threshold at $$1\,\rm kHz$$ as the reference of $$0\,\rm dB$$ used on many instruments.

You may also find the Wikipedia article Sound Power of interest.

• Thanks for clearing that up. I changed my post. If you use as a reference intensity just atmospheric pressure, how do you calculate the energy exactly? I look at the page but I can't seem to correctly figure it out. Thanks in advance Commented Jan 2, 2022 at 8:10
• @bananenheld It is impossible for a sound wave to have a amplitude equal to atmospheric pressure. Note that a sound wave can be thought of as a variation in pressure about atmospheric pressure. Commented Jan 2, 2022 at 8:14
• Ok thank you for clearing that mistake up. How can you calculate the energy then? Commented Jan 2, 2022 at 9:34
• Sound Intensity and Sound Level Commented Jan 2, 2022 at 9:53
• Looking at the "Sound Intensity and Sound Level" table you will see that the reference power per square metre, $10^{-12}$, is 0 dB. So 72 dB is a power per square metre of $10^{72/10} \times 10^{-12} \approx 1.6 \times 10^{-5}$ Commented Jan 2, 2022 at 10:33