In an elastic collision, I understand that momentum is conserved and kinetic energy is conserved. If billiard ball of silver (with velocity $v_{(Ag)}$ impacts a stationary billiard ball of aluminum, I am trying to calculate the velocity of the aluminum ball after the collision, $v_{(Al)}$. After an elastic collision, the impactor is at rest and the impactee has the motion.
Using momentum, $= m \cdot v$
$$m_{(Ag)} \cdot v_{(Ag)} = m_{(Al)} \cdot v_{(Al)}$$
Assuming silver is 4x denser than aluminium, then using momentum, the aluminium ball should have velocity
$$v_{(Al)} = 4\cdot v_{(Ag)}$$
But if we use kinetic energy, $1/2 m \cdot v^2$
$$\frac12m_{(Ag)}\cdot v_{(ag)}^2=\frac12m_{(Al)}\cdot v_{(Al)}^2$$
$$v_{(Al)}^2=\frac{m_{(Ag)}}{m_{(Al)}}\cdot v_{(Ag)}^2$$
$$v_{(Al)}=\left(\frac{m_{(Ag)}}{m_{(Al)}}\right)^{\frac12}\cdot v_{(Ag)}$$
$$v_{(Al)}=2\cdot v_{(Ag)}$$
Somewhere I have lost some neuron connections in my brain because I cannot resolve this conflict. This is a perfectly elastic collision so both momentum and kinetic energy should be conserved.
I have read multiple threads including:
When is energy conserved in a collision and not momentum?
How to calculate velocities after collision?
How can I calculate the final velocities of two spheres after an elastic collision?
Calculating new velocities of $n$-dimensional particles after collision
Velocities in an elastic collision
Summation of the velocities before and after an elastic collision