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Sorry, for my naivety this is my first time posting here. But, my question is that will the bulb offer any resistance after it's fused? I know that no current can flow though the fused bulb i.e. $I=0$. That makes $R = V/0$ undefined.

And voltage and total resistance stay the same, right? So, shouldn't the rest of the bulbs in the circuit get brighter? But that isn't the case and it turns out that the potential difference of the circuit decreases (to nullify the voltage increase on the other bulbs).

I'm very confused here, please help. Thank you.

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  • $\begingroup$ @my2cts If the bulb is broken, then $R=\infty$, not zero. Zero resistance is a completed current path, e.g., a superconducting wire. $\endgroup$
    – Bill N
    Commented Mar 13, 2021 at 15:53
  • $\begingroup$ What do you mean by "fused?" Do you mean a broken filament (in the case of an incandescent bulb)? Fused usually means one has placed a fuse device in the circuit, or one has joined two objects permanently,, similar to welding or soldering. $\endgroup$
    – Bill N
    Commented Mar 13, 2021 at 15:56
  • $\begingroup$ I have no clue what your circuit is but a broken bulb has R=$\infty$. If all the lights go out probably the whole circuit has R=$\infty$, possibly because of a blown fuse. $\endgroup$
    – my2cts
    Commented Mar 13, 2021 at 16:10
  • $\begingroup$ Your question lacks clarity in the sense that you talk about circuits but don't give any details about it. $\endgroup$
    – Cluse
    Commented Mar 13, 2021 at 19:29

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