2
$\begingroup$

OK for a system with spin $1/2$, if one measures $S_{x}$ the information on $S_{y}$ is lost and measuring $S_{y}$ after an $S_{x}$ measurement one gets a $50\%$ probability for $S_{y}$ up. My question is if $[S_{x},S_{y}]=i\hbar S_{z}$ has any other experimental implication. For example, if one measures $S_{y}$ then $S_{x}$ is there a meaning for $-S_{x}S_{y}$? If one measures $S_{y}$ then $S_{x}$ and then $S_{x}$ followed by $S_{y}$ do we get the "commutator"? After all we never get a projection of $S_{z}$ no matter how often we measure $S_{x}$ and $S_{y}$. And what is actually the meaning of $i \hbar S_{z}$? Does it make sense to multiply an operator with a complex-valued constant? I am aware the question may come across silly but I wonder if these non commutation relations mean something else than simply that one measurement "kills the information" for a following type of measurement.

$\endgroup$

1 Answer 1

2
$\begingroup$

My question is if $[S_x,S_y]=i\hbar S_z$ has any other experimental implication. For example, if one measures $S_y$ then $S_x$ is there a meaning for $−S_xS_y$?

You are right. This is highly abstract and hard to grasp in the context of the observables $S_x$, $S_y$ and $S_z$. But there is another way because these operators have two different roles:

  • They represent measurable physical observables (the components of spin angular momentum).
  • They generate rotations around the coordinate axes. For example: $R(\hat x,\alpha)=e^{-i\alpha S_x/\hbar}$ is a rotation around the $x$-axis by an angle $\alpha$.

These two roles are closely related to each other. Actually these are two aspects of the same thing. From the commutator relations between the spin operators, like $$[S_x,S_y]=i\hbar S_z$$ you can derive corresponding commutator relations between rotations, like $$R(\hat x,\alpha)R(\hat y,\beta)R(\hat x,-\alpha)R(\hat y,-\beta) \approx R(\hat z,-\alpha\beta) \quad \text{ if }\alpha,\beta\ll 1$$ Now this relation has a direct intuitive meaning (and there is no $i\hbar$ involved anymore). You can actually check this physically by doing the sequence of the 4 rotations ($R(\hat x,\alpha)$, $R(\hat y,\beta)$, $R(\hat x,-\alpha)$, $R(\hat y,-\beta)$) on a shoe-box. Then you will see, the rotations don't quite cancel, and the box does not exactly come back to its original orientation, but get a small rotation around the $z$-axis.

I wonder if these non commutation relations mean something else

The non-commutativity of rotations $$R(\hat x,\alpha)R(\hat y,\beta)\ne R(\hat y,\beta)R(\hat x,\alpha)$$ is a direct consequence of the non-commutativity of the spin components $$S_xS_y\ne S_yS_x.$$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.