I know that in polar coordinates, it is $\frac{\partial \,{{\mathbf{e}}_{r}}}{\partial \theta }={{\mathbf{e}}_{\theta }}$ and $\frac{\partial \,{{\mathbf{e}}_{\theta }}}{\partial \theta }=-{{\mathbf{e}}_{r}}$ where ${{\mathbf{e}}_{r}}$ and ${{\mathbf{e}}_{\theta }}$ are the basis unit vectors.
Anyway, using the definition of the connection coefficients (Christoffel symbols) it should also be
$\frac{\partial \,{{\mathbf{e}}_{r}}}{\partial \theta }={{\Gamma }^{r}}_{r\theta }\,{{\mathbf{e}}_{r}}+{{\Gamma }^{\theta }}_{r\,\theta }\,{{\mathbf{e}}_{\theta }}$ and $\frac{\partial \,{{\mathbf{e}}_{\theta }}}{\partial \theta }={{\Gamma }^{r}}_{\theta \,\theta }\,{{\mathbf{e}}_{r}}+{{\Gamma }^{\theta }}_{\theta \,\theta }\,{{\mathbf{e}}_{\theta }}$
And since it is ${{\Gamma }^{r}}_{\theta \,\theta }=-r$ , ${{\Gamma }^{\theta }}_{r\,\theta }=\frac{1}{r}$ , ${{\Gamma }^{r}}_{r\,\theta }=0$, ${{\Gamma }^{\theta }}_{\theta \,\theta }=0$ (calculated with the metric) it should be
$\frac{\partial \,{{\mathbf{e}}_{r}}}{\partial \theta }=\frac{1}{r}{{\mathbf{e}}_{\theta }}$ and $\frac{\partial \,{{\mathbf{e}}_{\theta }}}{\partial \theta }=-r\,{{\mathbf{e}}_{r}}$
Where am I wrong?