Consider the Langevin equation in the overdamped regime,
$$ 0 = -\gamma \dot{\mathbf{x}} -\nabla U(\mathbf{x}) +\boldsymbol{\eta}(t) \, $$
where $\boldsymbol{\eta}$ is the usual white-noise term, $U$ a potential for the force and $\gamma$ the damping coefficient (or a "damping matrix"). Note: thanks to the good reference provided in the accepted answer, I found how to derive the associated Fokker-Planck equation for this system.
Assuming that we have our Fokker-Planck equation for the particle distribution $P(\mathbf{x},t)$, I imagine (but I am not sure) that the average velocity of particles is given by
$$\langle \dot{\mathbf{x}}(t) \rangle = -\int d^Nx \, P(\mathbf{x},t) \gamma^{-1} \nabla U(\mathbf{x}). $$
Note that I am talking about the average velocity: the velocity of a single particle is not well defined for the overdamped case (the Brownian motion is non-differentiable).
Now here is my doubt: at $t=0$ we could choose a certain $P(\mathbf{x},0)$, find $P(\mathbf{x},t)$ with the Fokker Planck and calculate $\langle \dot{\mathbf{x}}(t) \rangle$ as above. Alternatively, we could sample $M$ different initial conditions $\mathbf{x}_i(0)$ from $P(\mathbf{x},0)$, evolve each $\mathbf{x}_i(t)$ for $i=1...M$ with the Langevin equation and obtain
$$\langle \dot{\mathbf{x}}(t) \rangle \approx M^{-1} \sum_i \dot{\mathbf{x}}_i(t) .$$
If this is correct, which method in general is more convenient from the numerical point of view? I see a big difference: simulating a single PDE (the Fokker-Planck) and performing an integral VS simulating a high number $M$ of ODEs (but performing a simple sum).
Related posts: Average velocity of overdamped particles in external field (MathSE), Understanding mean rate of change in Brownian motion, What does this observation of instantaneous velocity in Brownian particles mean?, Correlation of position and velocity in Brownian motion.