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Armchair physicist with a rudimentary understanding of physics here. I was watching a video today that tested the effects of a football filled with normal air, helium, and sulfur hexafluoride. Presumably, it is testing the gut assumption that a ball filled with less dense gas could be kicked farther than a ball filled with normal air and, conversely, a ball filled with a more dense gas would not go as far.

Here's the video in question

The parameters of the experiment are such. Three standard-size footballs (or as far as I can tell) are filled to $12\, \mathrm{psi}$ of each gas. Each of the balls are then subjected to a series of kicks of differing nature: inside kicks, toe kicks, and drop kicks. The experiment is run with multiple participants, and which ball flew the farthest on a particular style of kicks is recorded.

Now obviously, this experiment wasn't done with much rigor (three participants at five total kicks each), but the results were still somewhat surprising: it was recorded that the helium ball went the farthest in 8 of 15 kicks, but in second place was the sulfur hexafluoride with 6 out of 15 (normal air went the farthest in only 1 of 15).

This made me wonder if the type of gas used has any effect at all, and if this was a "pound of bricks vs pound of feathers" type of situation. The relevant formula seems to be the formula for the pressure of an ideal gas $P=\rho RT$. Since the only variable that changes between the three footballs (in theory, anyway) is the gas used, and that pressure and temperature are constant (also in theory, the balls could be allowed to rest after filling to ensure the temperatures are equal), that would mean the density must also be constant.

The main relevant difference between the three gases is their mass. In the formula, the mass would show up as the density $\rho$ in the form of $ρ= {m \over V}$. This would mean that, in order for density to remain constant, as mass goes up, the volume would have to go down. This would translate to each ball having to be filled with more helium and less sulfur hexafluoride than regular air in order to be filled to the same psi.

Therefore, even though the balls are being filled with gas that is either lighter or heavier than normal air, they would have to be filled with more or less of the gas respectively in order to compensate for the difference in density. As such, these effects would cancel out and the resulting weight of each ball would be more or less identical, leading to the three balls performing virtually identically.

How close am I in this, or am I totally off base? Am I completely misinterpreting the relevance of mass and volume in the formula? Is there some other effect that the different gases would have that would change how each ball performs in an appreciable way?

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  • $\begingroup$ Why do you think balloons are made of such light-weight material? $\endgroup$ Commented Nov 6, 2019 at 11:39
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    $\begingroup$ The $\rho$ in the ideal gas law is the number density (i.e. number of molecules per volume) not the mass density. $\endgroup$
    – TimRias
    Commented Nov 6, 2019 at 11:57
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    $\begingroup$ Re, "pound of bricks vs pound of feathers." But it's not that way at all. The helium filled ball will have less mass than the SF<sub>6</sub> filled ball. Less mass == less inertia, and inertia is the reason why the ball isn't immediately stopped by air resistance the moment it leaves the kicker's foot. (Hint: Go to a craft store, buy one of those styrofoam balls that people use to make Christmas ornaments, and see whether you can throw it farther than you can throw a baseball.) $\endgroup$ Commented Nov 6, 2019 at 14:25
  • $\begingroup$ I would suggest using a ball-kicking machine for this experiment. It would be more consistent than human being participants. $\endgroup$
    – verdelite
    Commented Nov 6, 2019 at 18:49
  • $\begingroup$ Before I clicked the video, I just assumed that it was a clip of that one episode of Mythbusters where they tested the same thing. They used American footballs and a football throwing machine for consistency, as well as having more trials. Their results is that the difference was statistically insignificant. $\endgroup$ Commented Nov 6, 2019 at 23:44

4 Answers 4

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DICLAIMER: I did this answer before watching the video. I am a silly American, and I took "football" to mean "American football". So my numbers are not exactly correct, but I think they are still within the same ballpark (American baseball?), so I believe my conclusions are still valid.


Before trying to draw conclusions from the data, let's think about if we would expect there to be much of a difference in how the ball travels depending on the gas it is filled with.

So there are multiple things that matter that has been mentioned either in your question or in the answers that have already been posted: The vertical force acting on the ball (essentially the effective "gravity" it feels), the effects of air resistance (the force will roughly be the same between balls, but a lighter ball will be affected more than a heavier ball), and the initial velocity of the ball (you would expect for the same kicking force that the lighter ball would start off moving faster than a heavier ball).

For each of these things, it will be useful to understand how the mass/weight of the football material compares to the mass/weight of the gas inside of it. According to this site a deflated football weighs roughly one pound which is about $4.5\,\mathrm N$.

The football is filled to a pressure of $12\,\mathrm{psi}\approx8\times10^4\,\mathrm{Pa}$. Adding in atmospheric pressure we get have a gas that is at a pressure of roughly $2\times10^5\,\mathrm{Pa}$. From this site we can estimate the volume of the football to be about $280\,\mathrm{in^3}\approx4.5\times10^{-3}\,\mathrm{m^3}$. Finally, using the ideal gas law assuming a ball at room temperature, the football will contain about $0.36$ moles of gas.

So let's look at the three gases in question. The molar mass of dry air is about $30\,\mathrm{g/mol}$, so this gives the mass of air to be roughly $10\,\mathrm g$ (confirmed by the first link above) and the weight of the air to be roughly $.1\,\mathrm N$. For helium we have $4\,\mathrm{g/mol}$ which gives a mass of roughly $1.5\,\mathrm g$ weight of roughly $.015\,\mathrm N$. And finally for sulfur hexafluoride we have about $150\,\mathrm{g/mol}$ which gives a mass of about $50\,\mathrm g$ and a weight of about $.5\,\mathrm N$.


Now for the analysis. The net vertical force (neglecting vertical air resistance) on the ball is given by $$F_y=F_b-w_B-w_g$$ where $F_b$ is the buoyant force, $w_B$ is the weight of the ball, and $w_g$ is the weight of the gas. The vertical acceleration is then $$a_y=\frac{F_b-w_B-w_g}{m_B+m_g}$$

The buoyant force is the same for all balls, it is just $\rho_\text{atmosphere}V_Bg\approx.05\,\mathrm N$. The mass and weight weight of the ball we already found as about $.45\,\mathrm kg$ and $4.5\,\mathrm N$. The mass and weight of each ball we also found above. The vertical accelerations for all of the balls is then $$a_\text{air}\approx-9.89\,\mathrm{m/s^2}$$ $$a_\text{He}\approx-9.89\,\mathrm{m/s^2}$$ $$a_\text{S}\approx-9.9\,\mathrm{m/s^2}$$

So it looks like the vertical accelerations are not very much different (at least not to the accuracy within my rounding).


What about the effects of air resistance and the kicking force on our balls? Well, this is determined by the total mass of the balls $m_B+m_g$, as the accelerations they feel from these forces is given by $a=F/m_\text{total}$. These total masses are easily determined

$$m_\text{air}\approx0.46\,\mathrm{kg}$$ $$m_\text{He}\approx0.45\,\mathrm{kg}$$ $$m_\text{S}\approx0.5\,\mathrm{kg}$$

Once again, I cannot see these making a huge difference, and this could be expected. The mass of just the ball materials is around $0.45\,\mathrm {kg}$ anyway, so I don't see changes of at most $.05\,\mathrm {kg}$ having a significant influence. Certainly we would not expect a noticeable difference between the air filled ball and the helium filled ball.


Ultimately, it looks like the material of the ball is massive enough so that the gas it is filled with will not have a huge impact on its travel. As @BobD discusses in his answer, what is likely happening here is that the "experiment" was not done with much precision in terms of similar conditions for the kicks, determining the distance of travel, etc. It is most likely just a ploy to get more views.

What would make their results better (but still not the best) is if they did a bunch of tests with the same type of ball and determined a distribution of distances for each ball. Then they should have compared the three distributions and see if the differences between the distributions were statistically significant. This would have been much better than just looking at which ball went the farthest, as this is not solely determined by the mass of the ball. I have confidence in my estimations, but as we all know, a well-executed experiment would be better and have the final say here.

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  • $\begingroup$ Woops. Drafted and posted an update to my answer before seeing yours. Once again, I think we are on the same track. $\endgroup$
    – Bob D
    Commented Nov 6, 2019 at 17:07
  • $\begingroup$ @BobD Yeah I agree. You could kick the same ball multiple times and could probably divide the data into balls that went far, balls that went short, etc. just based on how it was kicked. I think looking at the distributions like I mention at the end of my answer could be a little better, although that still wouldn't be ideal. $\endgroup$ Commented Nov 6, 2019 at 17:10
  • $\begingroup$ Yeah, there were just too many variables to reach any conclusions. $\endgroup$
    – Bob D
    Commented Nov 6, 2019 at 17:14
  • $\begingroup$ I'm also a silly American. I just figured that with PSE being an international audience I might avoid alienating some people by calling it a soccer ball. At any rate, this makes sense. Basically, there's virtually no difference in initial velocity, but a ball filled with more massive gas would be affected less by air resistance, thus traveling farther. That being said, the mass of the gas is so small compared to the ball itself that there isn't likely to be any perceptible difference in real-world performance. (i.e. No soccer player is likely going to even notice during an actual soccer game.) $\endgroup$
    – Abion47
    Commented Nov 6, 2019 at 19:36
  • $\begingroup$ @Abion47 Yes, that would be my guess. Unless a more involved experiment is done, I would say there isn't actually any difference here. $\endgroup$ Commented Nov 6, 2019 at 20:04
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Now obviously, this experiment wasn't done with much rigor (three participants at five total kicks each), but the results were still somewhat surprising: it was recorded that the helium ball went the farthest in 8 of 15 kicks, but in second place was the sulfur hexafluoride with 6 out of 15 (normal air went the farthest in only 1 of 15).

Having watched the video I'm not surprised at the results. I would find it hard to reach any scientifically based logical conclusions regarding the difference in performance between any of the balls based on the demonstration. In particular, the difference in performance between air and helium, compared to difference between helium and sulfur hexafluoride makes no sense to me.

There appears to be no measurement, or control, of the impact force associated with each kick. Nor any control over the angle of each kick relative to the ground. Some kicks resulted in launching the ball higher in the air. Others resulted in the ball flying low and bouncing along the ground. One ball hit a bush. Another hit a rock. Overall this is a terrible experiment and any attempt at a physics explanation to make sense of the results seems, at least to me, pointless.

The above being said, assuming each of the three soccer balls is identical in terms of the outer surface and the outside diameter, for a given velocity each ball should experience the same air drag force. After launch the only forces each soccer ball experiences are gravity and air drag.

The horizontal acceleration, for the same horizontal velocity, of each ball will be

$$a=-\frac{F_{r}}{M}$$

Where $F_r$ is the air drag force (same for each ball for the same horizontal velocity), and $M$ is the mass of the soccer ball (covering + enclosed gas). So for the same initial kick off velocity and same air drag force, the ball with the greatest mass should travel further. But by how much?

A regulation soccer ball has a mass of about 0.425 kg and a circumference of 70 cm. That equates an overall volume of about 0.0058 m$^3$. Neglecting the thickness of the wall, we can assume the volume is approximately equal to the volume of the enclosed gas. At 12 psig, assuming ideal gas behavior of each gas, and density proportional to pressure, the mass of each gas contained in the ball at 12 psig is approximately 0.0017 kg (helium), 0.013 kg (air) and 0.064 kg (sulfur hexafluoride).

Thus, the total mass of each soccer ball is about:

Helium filled: 0.427 kg; Air filled: 0.438 kg; sulfur hexafluoride: 0.489 kg.

If the initial horizontal velocity after being kicked is the same for each ball, given the small difference in masses of the balls, combined with all the other variables, it is unlikely to me there would be much of a difference between the performance of each. Perhaps the sulfur hexafluoride might travel somewhat further, all else being equal.

Hope this helps.

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  • $\begingroup$ I'm wondering if one factor to the helium ball going furthest is because the participants knew they were kicking the helium ball so they subconsciously kicked it a little harder in order to confirm their findings. $\endgroup$
    – Abion47
    Commented Nov 6, 2019 at 19:41
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    $\begingroup$ @Abion47 Could be, though I thought I heard on the video the guy say he didn't know which ball he was kicking. In any case, even if the person tried to kick each ball with the same force, we can still expect variations. Even the exact angle of impact will vary and that will change the results. Bottom line, there are so many experimental variables that, when coupled with the rather small differences in the mass of the three balls with different gases, are such we can hardly put much merit on the results of the demonstrationsl $\endgroup$
    – Bob D
    Commented Nov 6, 2019 at 19:46
  • $\begingroup$ I would think one would see more difference in distance as the altitude the ball is kicked at increases. The thinner air density at Denver and Mexico City allows baseballs, golf balls, American footballs, and even long jumpers to go further. $\endgroup$
    – CrossRoads
    Commented Nov 7, 2019 at 12:54
  • $\begingroup$ @CrossRoads Yes, that would make all three balls go farther. But would that make a difference in the difference in distance between the three balls. If you think it would, show the analysis to prove it. $\endgroup$
    – Bob D
    Commented Nov 7, 2019 at 13:09
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J Thomas gave a pretty good overview of why you might expect different results with the experiment.

I just want to point out the problem in your analysis. $$P = \rho R T$$

You seem to be looking at what wikipedia calls the molar form: $$P = \rho \frac R M T$$ where $M$ is the molar mass of the compound. In that case, you often define $R_{\text{specific}} = \frac R M$. That means the $R$ in your equation should actually be $R_{\text{specific}}$, which will change how $\rho$ and $V$ relate to each other depending on the gas (since $R_{\text{specific}}$ depends on the gas).

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  • $\begingroup$ I was actually looking at this site for the break down on the ideal gas law. This makes sense, though. $\endgroup$
    – Abion47
    Commented Nov 6, 2019 at 19:45
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    $\begingroup$ @Abion47 I wouldn't trust that site at all just reading what it shows about the ideal gas law. Their derivation appears to randomly remove or change things in the equation. They say $P \frac V m = \frac {nRT}{m}$ and then that $v = \frac V m = \frac 1 {\rho}$. So substituting we get $Pv = \frac {nRT}{m}$, for some reason, they change the $m$ on the right side to $M$. Then they just say "or" $Pv = RT$ and work from there... but that makes no sense. They are saying $RT = \frac {nRT}{m}$; which is only true when $n = m$; which is not guaranteed here at all. $\endgroup$
    – JMac
    Commented Nov 6, 2019 at 20:18
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If the pressure is constant, different gases will have different density. As a first approximation, at a given pressure, a mole of gas will have about the same volume for different gases.

So the different footballs will have different masses, and that should be the main difference between them. (The one filled with helium would leak faster.)

What difference does the different mass make? In vacuum, they should fall at the same speed. Maybe you could throw the lightest one farther.

In air, the lighter one should fall slower. If you had a non-regulation football that was light enough for the helium to make it bouyant, it wouldn't fall at all.

But also in air the lighter one should slow down faster. Air resistance on the same surface area would be the same, and there would be less inertia opposing it. So in vacuum the path should be a parabola, and in air it would fall short.

So that's three differences. With helium it might start faster, and fall slower, but slow down faster too.

I can't tell you which of those would be more important. How fast you can kick it might be limited more by your leg than by the weight.

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