Armchair physicist with a rudimentary understanding of physics here. I was watching a video today that tested the effects of a football filled with normal air, helium, and sulfur hexafluoride. Presumably, it is testing the gut assumption that a ball filled with less dense gas could be kicked farther than a ball filled with normal air and, conversely, a ball filled with a more dense gas would not go as far.
The parameters of the experiment are such. Three standard-size footballs (or as far as I can tell) are filled to $12\, \mathrm{psi}$ of each gas. Each of the balls are then subjected to a series of kicks of differing nature: inside kicks, toe kicks, and drop kicks. The experiment is run with multiple participants, and which ball flew the farthest on a particular style of kicks is recorded.
Now obviously, this experiment wasn't done with much rigor (three participants at five total kicks each), but the results were still somewhat surprising: it was recorded that the helium ball went the farthest in 8 of 15 kicks, but in second place was the sulfur hexafluoride with 6 out of 15 (normal air went the farthest in only 1 of 15).
This made me wonder if the type of gas used has any effect at all, and if this was a "pound of bricks vs pound of feathers" type of situation. The relevant formula seems to be the formula for the pressure of an ideal gas $P=\rho RT$. Since the only variable that changes between the three footballs (in theory, anyway) is the gas used, and that pressure and temperature are constant (also in theory, the balls could be allowed to rest after filling to ensure the temperatures are equal), that would mean the density must also be constant.
The main relevant difference between the three gases is their mass. In the formula, the mass would show up as the density $\rho$ in the form of $ρ= {m \over V}$. This would mean that, in order for density to remain constant, as mass goes up, the volume would have to go down. This would translate to each ball having to be filled with more helium and less sulfur hexafluoride than regular air in order to be filled to the same psi.
Therefore, even though the balls are being filled with gas that is either lighter or heavier than normal air, they would have to be filled with more or less of the gas respectively in order to compensate for the difference in density. As such, these effects would cancel out and the resulting weight of each ball would be more or less identical, leading to the three balls performing virtually identically.
How close am I in this, or am I totally off base? Am I completely misinterpreting the relevance of mass and volume in the formula? Is there some other effect that the different gases would have that would change how each ball performs in an appreciable way?