We apply a force to a particle with a mass $m$ and inicial velocity $v_0$:
$$ F(t) = \left \{ \begin{matrix} 0 & \mbox{ $t<t_0$} \\ \frac{p_0}{\delta t} & \mbox{ $t_0<t<t_0 +\delta t$}\\ 0 & t_0+\delta t<t\end{matrix}\right. $$
(a) Find $v(t)$ and $x(t)$
(b) Show that the movement reach a constant velocity when $dt\rightarrow 0$ at $t=t_0$
My main question is:
How do I work with $\delta t$?
I suposed that $\delta t$ is a constant, so:
$$F(t)=\frac{p_0}{\delta t}=m\cdot a(t)$$
$$a(t)=\frac{dv}{dt}(t)=\frac{F(t)}{m}$$
Integrating: $$\int_{v_0}^{v}dv= \int_{t_0}^{t_0+\delta t}\frac{1}{m}F(t)dt=\frac{1}{m}\int_{t_0}^{t_0+\delta t}\frac{p_0}{\delta t} dt$$
$$ v-v_0=\frac{p_0}{m\delta t}\left[ t\right]_{t_0}^{t_0+\delta t}= \frac{p_0}{m\delta t}\left[ t_0+\delta t-t_0\right] $$
So
$$\fbox{$v(t)=v_0 + \frac{p_0}{m}$}$$
Knowing that $v(t)=dx(t)/dt$, we calculate in the same form $x(t)$ by integration, I obtain:
$$\fbox{$x(t)=x_0+v_0 \delta t + \frac{p_0}{m}\delta t$}$$
Is this correct?
How do I demostrate the second question?