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I have read these questions:

At what distance could you see andromeda with the naked eye?

Do all the individual stars that we can see in the night sky belong to Milky Way?

I look at the night sky and I can only see stars, no galaxies. And from these questions I learned that even those stars are from the Milky way.

Now, these questions do not talk about the actual QM reasons why some distant stars are visible or not. It must be about intensity of photons. The more intensity a light source has, the more chance of a single photon to reach Earth and our eyes.

Now the human eye can detect even single photons.

A galaxy is made up of billions of stars, so there are billions of light sources, all of them emitting billions of times more photons then a single star.

How is it then possible that we can see single stars, but not galaxies with the naked eye?

A galaxy has billions of light sources, emitting billions of times more photons, and even if one single photon reaches our eyes, we would see it.

From a single star, the chances are billions of times smaller, simply because of intensity.

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Question:

  1. How is it possible that a single star as light source is visible, but a whole galaxy with billions of light sources is not visible with the naked eye?

  2. It is unbelievable that the moon is smaller then the Andromeda galaxy, still Andromeda is not visible at all. Andromeda has billions of stars, each emitting photons, so the intensity must be much higher then of the moon. Why can't I see it then? Our eyes would catch even a single photon from Andromeda.

  3. What happens to all those photons from Andromeda? Do they all get blue-shifted to infinity?

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    $\begingroup$ You have multiple mistakes in your reasoning, but the biggest one of them is that yes, on a really dark night in a really dark location, it is indeed possible to make out Andromeda with the naked eye. $\endgroup$
    – Kphysics
    Commented Apr 17, 2019 at 21:59
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    $\begingroup$ What do you mean? The accepted answer to your 2nd linked question mentions that Andromeda and the Magellanic Clouds are all visible to the naked eye as fuzzy blobs. But you do need to be in a region with low light pollution. Forget trying to see them in a city polluted with electric lighting. And of course you need to be sufficiently far south to see the Magellanic Clouds. To my eyes, they look like little chunks separated from the main "stream" of the Milky Way. $\endgroup$
    – PM 2Ring
    Commented Apr 17, 2019 at 22:08
  • $\begingroup$ I've removed a couple of comments which answered the question. To answer the question, please post an answer. $\endgroup$
    – rob
    Commented Apr 17, 2019 at 23:01
  • $\begingroup$ Well,easy to say..The galaxies are very far from us compared to the moon,sun etc $\endgroup$
    – Dee
    Commented Aug 13, 2023 at 9:06

2 Answers 2

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1) There are $10^{12}$ stars in Andromeda.

2) Let's assume that on average, they emit as much light as the sun. So Andromeda emits $10^{12}$ times as much light as the sun does.

3) The sun is about 400 times as far away as the moon.

4) The intensity of light falls off with the square of the distance. Therefore light we get from the sun is diluted by $400^2=160,000$ times as much as light from the moon.

5) From earth, the apparent brightness of the sun is 400,000 times the apparent brightness of the moon. Therefore the sun emits about $400,000 \times 160,000\approx 6\times 10^{10}$ times as much light as the moon reflects. Call it $10^{10}$.

6) By 2) and 5), Andromeda emits about $10^{12}\times 10^{10}=10^{22}$ times as much light as the moon reflects.

7) Andromeda is about $10^{15}$ times as far as the moon.

8) Therefore light coming from Andromeda is diluted about $10^{30}$ times as much as light coming from the moon.

9) So if we compare Andromeda to the moon, we have $10^{22}$ times as much light (by point 6)), diluted $10^{30}$ times as much (by point (8)).

10) $10^{22}$ divided by $10^{30}$ is $10^{-8}$, or one over a hundred million. Therefore Andromeda should appear about one one-hundred-millionth as bright as the moon.

By these (very) rough calculations, it's a bit surprising that we can see Andromeda at all.

Edited to add: I'm sure that nevertheless, photons from Andromeda have hit your eye, and probably your brain has detected them. But your brain has no way of knowing that a stray photon came from Andromeda. It needs enough photons to reconstruct a picture, and at least if the above is roughly right, it's only got one one-hundredth-million as many as it uses to reconstruct a picture of the moon.

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    $\begingroup$ The fact that we can see Andromeda from really dark sites indicates that enough photons to potentially reconstruct a picture do arrive. But they are usually lost in the foreground glare of the night sky (just as we can see nearby stars at night but not during the day), which is the only thing missing in your otherwise excellent answer. $\endgroup$ Commented Apr 18, 2019 at 10:04
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  1. Intensity is not some type of probability function. It is a measure of the spread of a light source or brightness (J/m^2).
  2. These galaxies are very far away
  3. Since the galaxies are so far away the intensity of light reaching our eyes at this distance is ridiculously small
  4. Combine this with light pollution in cities and our eyes are too overloaded to see galaxies.
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  • $\begingroup$ I was thinking of intensity in the number of photons as per QM. I still do not know what happens to those photons coming from Andromeda, are they redshifted or why can't we see them? $\endgroup$ Commented Apr 18, 2019 at 3:01
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    $\begingroup$ The effects of distance dilution are the same if you think in terms of number of photons. So the problem is: too few photons reaching your eye, compared with all the photons from the night sky that reach your eye at the same time. $\endgroup$ Commented Apr 18, 2019 at 9:58

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