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If I have 2 squares each with random velocities, and both with the same mass, would it be possible to calculate their velocities after a collision, and how would I do so?

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    $\begingroup$ Do you mean squares or spheres? $\endgroup$ Commented Mar 3, 2019 at 12:09

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Yes it is possible . The only condition is that no mechanical energy must be lost.

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    $\begingroup$ Thanks for your quick answer, I was actually looking for how to do it though, and have edited my question. $\endgroup$
    – Sarah
    Commented Mar 3, 2019 at 11:48
  • $\begingroup$ I will tell ypu how to do it . Since no mechanical energy is lost the mechanical energy of the system remains the same . Also because no external forces are applied to your system the total momentum of the system remains the same ( always assuming that the contact between the 2 spheres happened instantly). I am letting you think first for a while on how you will solve it . If you still cant I will give you a mathematical description it ok?( despite the fact I really hate math) $\endgroup$ Commented Mar 3, 2019 at 11:57
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    $\begingroup$ How would I calculate the velocities after the collision happened, and how would the energy be distributed on contact? $\endgroup$
    – Sarah
    Commented Mar 3, 2019 at 12:00
  • $\begingroup$ Assume your 2 spheres have the same distance from the ground and they move only horizontally. We say that the first sphere is m1 and has a velocity of u1 .The second sphere is m2 and has a velocity of u2 . 1/2m1*u1^2 + 1/2m2*u2^2 = 1/2m1*u1'^2+1/2m2*u2'^2 since no energy is lost $\endgroup$ Commented Mar 3, 2019 at 12:07
  • $\begingroup$ m1*u1 + m2*u2 = m1*u1'+m2*u2' from the law of conservatipn of total momentum if no external force is applied $\endgroup$ Commented Mar 3, 2019 at 12:09

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