# Rest frame of massive photon in Meissner–Ochsenfeld effect

The Meissner–Ochsenfeld effect together with spontaneous symmetry breaking and the London Equation yields

$$(\Box+M^2)A^\mu=0$$

and gives photon an effective mass

$$q\sqrt{\frac{n_c}{m_c}}$$

Which is a process almost identical to the Higgs mechanism

My question is, similar to the massive W and Z boson, does the effective mass make it possible to find a rest frame for the massive photon? If yes, how can we interpret the massive photon at rest more intuitively?(from the perspective of electromagnetism for example)

In the rest frame of your static superconductor, $$\nabla\cdot \vec{J}=0$$, so you are in the London gauge, $$\nabla\cdot \vec{A}=0$$. As a consequence, Ampere's law reduces to $$\nabla^2 \vec {A}= \frac{1}{\xi^2} \vec {A},$$ whose curl nets $$\nabla^2 \vec {B}= \frac{1}{\xi^2} \vec {B},$$ solved by the standard attenuated penetration into the superconductor, $$\vec {B}= \vec {B}_0 ~e^{-x/\xi}.$$ Your massive photon has never failed to be at rest. What is the point of moving your system?