$v_{rms}$ of an ideal gas is given by $\sqrt{\dfrac{3RT}{M}}$ .
Now I believe that this depends only on temperature and molar mass of the gas. But someone told me to write RT as $\dfrac{PV}{n}$, then the formula would show pressure dependency at constant volume. But I still believe that it shows only direct temperature dependency because pressure of an ideal gas at constant volume can only(?) be increased by increasing the temperature.
Now, I am just wondering if there's a method to increase the pressure of the gas without us raising the temperature. I mean that the pressure should increase and then the temperature should increase as a result of Gay-Lussac's pressure law (not the other way round).
I think then the claim that $v_{rms}$ depends on pressure will be valid.